CODE USING C++ 4. Find the Elephant by CodeChum Admin When dealing with problems, it is always best to find the "elephant" in the room. The elephant is basically the biggest issue.   Once this is resolved, it's almost always easier to move forward.   As a therapist, I know how to find the elephant in the room. However, I'm feeling sick today and the next client is coming. Could you please find the elephant for me?   Instructions: In the code editor, you are provided with a function, findElephant() that accepts a 2D array and returns the largest element in the array. This function has already been implemented so do not edit this. You are also provided with the 2D array in the main() function. Your only task is to call the findElephant() function and pass the 2D array, and print the return value. Output Elephant:·10   EDIT THIS CODE:   #include #include using namespace std; int findElephant(int[][100]); int main(void) {     int matrix[100][100] = {         {1, 3, 33, 109, 2, 65, 32, 28, 129, 75},         {2, 44, 59, 8, 231, 632, 55, 205, 98, 1},         {76, 2, 321, 16, 209, 65, 12, 167, 259, 29},         {0, 103, 99, 3, 2, 65, 32, 321, 53, 75},         {44, 264, 50, 7, 142, 65, 100, 28, 98, 33},         {87, 22, 99, 67, 22, 412, 99, 502, 52, 24},         {91, 93, 233, 101, 330, 65, 98, 28, 98, 76},         {12, 65, 59, 99, 2, 65, 32, 333, 10, 88},         {3, 24, 101, 331, 542, 65, 32, 239, 338, 175},         {76, 3, 59, 21, 229, 65, 32, 28, 98, 75},     };          return 0; } // NOTE: DO NOT EDIT THIS FUNCTION int findElephant(int arr[][100]) {     int largest = INT_MIN;     for(int row = 0; row < 100; row++) {         for(int col = 0; col < 100; col++) {             if(arr[row][col] > largest) {                 largest = arr[row][col];             }         }     }          return largest;

EBK JAVA PROGRAMMING
9th Edition
ISBN:9781337671385
Author:FARRELL
Publisher:FARRELL
Chapter4: More Object Concepts
Section: Chapter Questions
Problem 2RQ
icon
Related questions
Question

CODE USING C++

4. Find the Elephant

by CodeChum Admin

When dealing with problems, it is always best to find the "elephant" in the room. The elephant is basically the biggest issue.

 

Once this is resolved, it's almost always easier to move forward.

 

As a therapist, I know how to find the elephant in the room. However, I'm feeling sick today and the next client is coming. Could you please find the elephant for me?

 

Instructions:

  1. In the code editor, you are provided with a function, findElephant() that accepts a 2D array and returns the largest element in the array. This function has already been implemented so do not edit this.
  2. You are also provided with the 2D array in the main() function.
  3. Your only task is to call the findElephant() function and pass the 2D array, and print the return value.

Output

Elephant:·10
 
EDIT THIS CODE:
 

#include <iostream>
#include <climits>
using namespace std;

int findElephant(int[][100]);

int main(void) {
    int matrix[100][100] = {
        {1, 3, 33, 109, 2, 65, 32, 28, 129, 75},
        {2, 44, 59, 8, 231, 632, 55, 205, 98, 1},
        {76, 2, 321, 16, 209, 65, 12, 167, 259, 29},
        {0, 103, 99, 3, 2, 65, 32, 321, 53, 75},
        {44, 264, 50, 7, 142, 65, 100, 28, 98, 33},
        {87, 22, 99, 67, 22, 412, 99, 502, 52, 24},
        {91, 93, 233, 101, 330, 65, 98, 28, 98, 76},
        {12, 65, 59, 99, 2, 65, 32, 333, 10, 88},
        {3, 24, 101, 331, 542, 65, 32, 239, 338, 175},
        {76, 3, 59, 21, 229, 65, 32, 28, 98, 75},
    };
    
    return 0;
}

// NOTE: DO NOT EDIT THIS FUNCTION
int findElephant(int arr[][100]) {
    int largest = INT_MIN;

    for(int row = 0; row < 100; row++) {
        for(int col = 0; col < 100; col++) {
            if(arr[row][col] > largest) {
                largest = arr[row][col];
            }
        }
    }
    
    return largest;
}

main.cpp
< > + C+
4. Find the Elephant
1 #include <iostream>
by CodeChum Admin
2 #include <climits>
using namespace std;
When dealing with problems, it is always best to find the "elephant" in the room. The
4
elephant is basically the biggest issue.
5 int findElephant(int[][100]);
Once this is resolved, it's almost always easier to move forward.
7 int main(void) {
int matrix[100][100] = {
{1, 3, 33, 109, 2, 65, 32, 28, 129, 75},
{2, 44, 59, 8, 231, 632, 55, 205, 98, 1},
{76, 2, 321, 16, 209, 65, 12, 167, 259, 29},
{0, 103, 99, 3, 2, 65, 32, 321, 53, 75},
{44, 264, 50, 7, 142, 65, 1өө, 28, 98, 33},
{87, 22, 99, 67, 22, 412, 99, 502, 52, 24},
{91, 93, 233, 101, 330, 65, 98, 28, 98, 76},
{12, 65, 59, 99, 2, 65, 32, 333, 10, 88},
{3, 24, 101, 331, 542, 65, 32, 239, 338, 175},
{76, 3, 59, 21, 229, 65, 32, 28, 98, 75},
};
8.
As a therapist, I know how to find the elephant in the room. However, I'm feeling sick
today and the next client is coming. Could you please find the elephant for me?
10
11
12
Instructions:
13
14
1. In the code editor, you are provided with a function, findElephant () that
accepts a 2D array and returns the largest element in the array. This function
has already been implemented so do not edit this.
17
2. You are also provided with the 2D array in the main() function.
18
3. Your only task is to call the findElephant () function and pass the 2D array,
19
20
and print the return value.
21
return 0;
22 }
23
Output
24 // NOTE: DO NOT EDIT THIS FUNCTION
25 int findElephant (int arr[][100]) {
int largest = INT_MIN;
26
Elephant: 10
27
28
for (int row - 0; row < 100; row++) {
29
for (int col = 0; col < 100; col++) {
if(arr[row][col] > largest) {
largest = arr[row][col];
}
30
31
32
33
34
}
35
36
return largest;
37 }
567 00
Transcribed Image Text:main.cpp < > + C+ 4. Find the Elephant 1 #include <iostream> by CodeChum Admin 2 #include <climits> using namespace std; When dealing with problems, it is always best to find the "elephant" in the room. The 4 elephant is basically the biggest issue. 5 int findElephant(int[][100]); Once this is resolved, it's almost always easier to move forward. 7 int main(void) { int matrix[100][100] = { {1, 3, 33, 109, 2, 65, 32, 28, 129, 75}, {2, 44, 59, 8, 231, 632, 55, 205, 98, 1}, {76, 2, 321, 16, 209, 65, 12, 167, 259, 29}, {0, 103, 99, 3, 2, 65, 32, 321, 53, 75}, {44, 264, 50, 7, 142, 65, 1өө, 28, 98, 33}, {87, 22, 99, 67, 22, 412, 99, 502, 52, 24}, {91, 93, 233, 101, 330, 65, 98, 28, 98, 76}, {12, 65, 59, 99, 2, 65, 32, 333, 10, 88}, {3, 24, 101, 331, 542, 65, 32, 239, 338, 175}, {76, 3, 59, 21, 229, 65, 32, 28, 98, 75}, }; 8. As a therapist, I know how to find the elephant in the room. However, I'm feeling sick today and the next client is coming. Could you please find the elephant for me? 10 11 12 Instructions: 13 14 1. In the code editor, you are provided with a function, findElephant () that accepts a 2D array and returns the largest element in the array. This function has already been implemented so do not edit this. 17 2. You are also provided with the 2D array in the main() function. 18 3. Your only task is to call the findElephant () function and pass the 2D array, 19 20 and print the return value. 21 return 0; 22 } 23 Output 24 // NOTE: DO NOT EDIT THIS FUNCTION 25 int findElephant (int arr[][100]) { int largest = INT_MIN; 26 Elephant: 10 27 28 for (int row - 0; row < 100; row++) { 29 for (int col = 0; col < 100; col++) { if(arr[row][col] > largest) { largest = arr[row][col]; } 30 31 32 33 34 } 35 36 return largest; 37 } 567 00
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 1 images

Blurred answer
Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question

The output must be Elephant: 10 not 632.

Solution
Bartleby Expert
SEE SOLUTION
Knowledge Booster
Declaring and Defining the Function
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
EBK JAVA PROGRAMMING
EBK JAVA PROGRAMMING
Computer Science
ISBN:
9781337671385
Author:
FARRELL
Publisher:
CENGAGE LEARNING - CONSIGNMENT