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Choose the correct value of months_of_year[-3] from the python list statement below. %3D months of year ['Jan', 'Feb', 'Mar', 'Apr'] O a. Apr O b. Feb O C. Jan O d. Mar

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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# python Date = [ { "createdAt": "2022-05-23T18:09:37", "balance": 1000000 }, { "createdAt": "2022-05-23T14:18:39", "balance": 1000000 }, { "createdAt": "2022-05-23T11:43:55", "balance": 90 }, { "createdAt": "2022-05-18T12:18:33", "balance": 2000000 }, { "createdAt": "2022-05-18T12:17:58", "balance": 10000000 }, { "createdAt": "2022-05-10T12:08:10", "balance": 79086 }, { "createdAt": "2022-05-10T12:07:14", "balance": 1111 }, { "createdAt": "2022-05-02T11:28:03", "balance": 13200 }, { "createdAt": "2022-04-21T11:47:08", "balance": 3000 }, { "createdAt": "2022-04-21T11:46:16", "balance": 6800 }, { "createdAt": "2022-04-21T11:33:26", "balance": 6000 }, { "createdAt": "2022-04-21T11:22:37", "balance": 5000 }, { "createdAt": "2022-04-21T11:21:48", "balance": 8000 }, { "createdAt": "2022-04-21T11:18:39", "balance": 7000 } ] # desire output [ { "createdAt": "2022-05-23", "balance": 2000090 }, { "createdAt": "2022-05-18", "balance": 12000000 }, { "createdAt": "2022-05-10", "balance": 80197…
Code is here- def validate_name(passed_name): '''This function is used to validate the first and last name''' valid = False valid_chars = ['"', '\''] for character in passed_name: if character.isalpha() or character.isspace() and character in valid_chars: valid = True else: valid = False break return valid def validate_company(passed_model): '''This function is used to test the company name''' bad_chars = ['"'] if passed_model: for character in passed_model: if character in bad_chars: print("Company name is incorrect. Please try again. ") return False return True else: print("Please try again.") return False def validate_address(passed_model): '''This function is used to validate the vehicle model''' bad_chars = [ "!", '"', "@", "$", "%", "^", "$", "*", "_", "=", "+", "<", ">", "?", ";", "[", "]", "{", "}"] if passed_model: for character in passed_model: if character in bad_chars: print("Address is incorrect. Please try again.") return False return True else:…
In Python, team_abbv = ['ARI', 'ATL', 'BAL', 'BUF', 'CAR', 'CHI', 'CIN', 'CLE', 'DAL', 'DEN', 'DET', 'GB', 'HOU', 'IND', 'JAX', 'KC', 'LAC', 'LA', 'MIA', 'MIN', 'NE', 'NO', 'NYG', 'NYJ', 'OAK', 'PHI', 'PIT', 'SEA', 'SF', 'TB', 'TEN', 'WAS'] A. Print the teams that begin with the letter "N" from the list team_abbv (the above abbreviations.) Sample output: Answer NE NO NYG NYJ B. How many teams' names begin with the letter "A"? Print out "There are x teams with the letter ‘A’ in their name”- x being the amount of teams. Sample output: Answer There are 12 teams with the letter 'A' in their name.
Common Time Zones Function Name: commonTimeZones() Parameters: code1( str ) , code2( str ) Returns: list of common time zones ( list ) Description: You and your friend live in different countries, but you figure there's a chance that both of you might be in the same time zone. Thus, you want to find out the list of possible time zones that you and your friend could both be in. Given two country codes, write a function that returns a list of the time zones the two countries have in common. Be sure not to include any duplicate time zones. If the two country codes do not have any common time zones, return the string 'No Common Time Zones' instead. Note: You can assume that the codes will always be valid. example test cases: >>> commonTimeZones('can', 'usa') ['UTC-08:00', 'UTC-07:00', 'UTC-06:00', 'UTC-05:00', 'UTC-04:00'] >>> commonTimeZones('rus', 'chn') ['UTC+08:00'] For this assignment, use the REST countries API…
Common Time Zones Function Name: commonTimeZones() Parameters: code1( str ), code2( str) Returns: list of common time zones ( list ) Description: You and your friend live in different countries, but you figure there's a chance that both of you might be in the same time zone. Thus, you want to find out the list of possible time zones that you and your friend could both be in. Given two country codes, write a function that returns a list of the time zones the two countries have in common. Be sure not to include any duplicate time zones. If the two country codes do not have any common time zones, return the string 'No Common Time Zones' instead. Note: You can assume that the codes will always be valid. example test cases: >>> commonTimeZones('can', 'usa') [UTC-08:00', 'UTC-07:00', 'UTC-06:00', 'UTC-05:00', 'UTC-04:00] >>> commonTimeZones('rus', 'chn') [UTC+08:00] For this assignment, use the REST countries API (https://restcountries.com/#api-endpoints-v2). For all of your requests, make…
please only c code dont use c++ and c#. * Function: create_restaurant * Function: search_restaurants * Function: update_restaurants * Function: print_restaurant * Function: delete_restaurants write the functions according to the given parameters. #include <stdio.h>#include <stdlib.h>#include <string.h> #define N 2000#define D 250 // A simple restaurant structuretypedef struct{char restaurant_name[15];double rating;char city[31];unsigned short opening_year;} RESTAURANT_t, *RESTAURANT; // Arraylist structuretypedef struct ArrayList_s{void **list;int size;int capacity;int delta_capacity;} ArrayList_t, *ArrayList; /*** Function: create_restaurant* ---------------------------* This function creates a restaurant with the given parameters. Rating of the restaurant which is a rational number between 0 and 10.*/RESTAURANT create_restaurant(char *restaurant_name, double rating, char *city, unsigned short opening_year){// TODO: Fill this block. } * Function:…
PYTHON CODING This function takes a list of points and then returns a new list of points, which starts with the first point that was given in the list, and then followed by points closest to the start point. Here is the function that needs to be created: def solution_path(points) : # insert code here return path Please use any of the following function to develop the solution_path function Distance function - calculates the distance between two points def distance(p1, p2) : distance = sqrt (((p1 [0] - p2 [0]) **2) + ((p1 [1] - p2 [1]) **2)) return (distance) Find_closest function - calculates the closest point to the starting point def find_closest(start_point, remaining_points): closest_distance = 99999 for coordinate in remaining_points: dist = distance(start_point, coordinate) if(dist < closest_distance): closest_distance = dist closest_point = coordinate return closest_point Path_distance function -…
In Python, grades_dict = {'Wally': [87,96,70], 'Eva': [100,87,90], 'Sam': [94,77,90], 'Katie': [100,81,82], 'Bob': [83, 65, 85]} write your own describe function that produces thesame 8 statistical results, for each one of the columns, that the built-in describe() function does.Note 1: Use the sample standard deviation formula (that is, the denominator is: N-1)Note 2: Your algorithm should work for any number of columns not just for 5Note 3: You can use the np.percentile() for the 25% and 75% percentile as well as the sort()built-in functions
Python Returning function function name: is_prime parameters: a number n returns: True if n is prime behavior: Check the values in the range [2, n) and return False if n is divible by any of them. function name: bound_0_to_100 parameters:a number grade returns: the grade with a minimum of 0 and a maximum of 100 behavior: In addition to exceeding 100, sometimes a grade will be so spectacularly bad that it falls below 0. In that case we want to normalize it to 0 so all grades fall into the range [0, 100]. ex: bound_0_to_100(75) returns 75, bound_0_to_100(103) returns 100, and bound_0_to_100(-5) returns 0 function name: bigger parameters: two values a and b returns: whichever of the two is greatest behavior: ex: bigger(3, 9) returns 9
In Python, grades_dict = {'Wally': [87,96,70], 'Eva': [100,87,90], 'Sam': [94,77,90], 'Katie': [100,81,82], 'Bob': [83,65,85]} Write your own describe function that produces the same 8 statistical results, for each one of the columns, that the built-in describe() function does. Note 1: Use the sample standard deviation formula (that is, the denominator is: N-1) Note 2: Your algorithm should work for any number of columns not just for 5 Note 3: You can use the np.percentile() for the 25% and 75% percentile as well as the sort() built-in functions
Brussel's choice def brussels_choice_step(n, mink, maxk): This problem is adapted from another jovial video "The Brussel's Choice" of Numberphile (a site so British that you just know there has to be a Trevor and a Colin somewhere in there) whose first five minutes you should watch to get an idea of what is going on. This function should compute and return the list of all numbers that the positive integer n can be converted to by treating it as a string and replacing some substring m of its digits with the new substring of either 2*m or m/2, the latter substitution allowed only when m is even so that dividing it by two produces an integer. This function should return the list of numbers that can be produced from n in a single step. To keep the results more manageable, we also impose an additional constraint that the number of digits in the chosen substring m must be between mink and maxk, inclusive. The returned list must contain the numbers in ascending sorted order.
In Python, grades_dict = {'Wally': [87,96,70], 'Eva': [100,87,90], 'Sam': [94,77,90], 'Katie': [100,81,82], 'Bob': [83, 65, 85]} Ask user to enter the names of the rows, i.e., indices. You can use: len(grades) to get the number of rows of the DataFrame. In addition, using the sort_index() method, ask user whether they wish to sort by rows or by columns and whether to sort in ascending or descending order (do not use any if-else statements)