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Choose the allowable Combination of quam tum number for an electrons ? (1) m = 5 1 = 0, me =0. (1) 3=4 1=0 me= 1 A (1²) m=5. I = 5 l=2 (iv) m = 3, (v) m = 3, I = (1) 2=2, 1 = 0 " m₁ = = 1/2 + 12 + 1/₂ ms= -2, me = 1 ms = + 1/₂ /2 + me=0 ms=1 21 = 0 , me = 1 ms=-1 1 ms= 1

Choose the allowable Combination of quam tum number for an electrons ? (1) m = 5 1 = 0, me =0. (1) 3=4 1=0 me= 1 A (1²) m=5. I = 5 l=2 (iv) m = 3, (v) m = 3, I = (1) 2=2, 1 = 0 " m₁ = = 1/2 + 12 + 1/₂ ms= -2, me = 1 ms = + 1/₂ /2 + me=0 ms=1 21 = 0 , me = 1 ms=-1 1 ms= 1

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter7: Quantum Theory Of The Atom
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Choose the allowable Combination of quam tum number for an electrons ? ms: - 1 l=0, me -0. 0, f = 0, me = (1) m = 5₁ l = (IP) 3=4 (v) m = 3, (vi) n=2, (11i) m = 5 ~ 1=5 (iv) m = 3, 2nd = 0 I = 2, me = 1 -2,m1 = 1 = e- 1=0 + 1 me=0 Ms = - 1/1/2 ms= 2 m₂ = + 1₂2 + ½/₂ ms= m₁ = + 1/₂2 1 ms = 1
Transcribed Image Text:Choose the allowable Combination of quam tum number for an electrons ? ms: - 1 l=0, me -0. 0, f = 0, me = (1) m = 5₁ l = (IP) 3=4 (v) m = 3, (vi) n=2, (11i) m = 5 ~ 1=5 (iv) m = 3, 2nd = 0 I = 2, me = 1 -2,m1 = 1 = e- 1=0 + 1 me=0 Ms = - 1/1/2 ms= 2 m₂ = + 1₂2 + ½/₂ ms= m₁ = + 1/₂2 1 ms = 1
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