A solution containing 0.18 M Pb²+ , 1.5 × 10-6 M Pb+, 1.5 × 10-6 M Mn²+ , 0.18 M MnO, , and 0.90 M HNO, was prepared. For this solution, the balanced reduction half-reactions and overall net reaction shown can occur. 5 [Pb4+ + 2e- Pb²+] 2 [MnO, + 8 H* + 5e¯ = Mn²+ + 4 H,O] 5 Pb+ + 2 Mn²+ + 8 H,0 =5 Pb²+ + 2 MnO, + 16 H* E; = 1.690 V E = 1.507 V Determine E, AG, and K for this reaction. cell

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Chapter17: Electrochemistry
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Problem 10E: Why is it not possible for hydroxide ion (OH-) to appear in either of the half-reactions or the...
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A solution containing 0.18 M Pb²+ , 1.5 × 10-6 M Pb+, 1.5 × 10-6 M Mn²+ , 0.18 M MnO, , and 0.90 M HNO, was
prepared. For this solution, the balanced reduction half-reactions and overall net reaction shown can occur.
5 [Pb4+ + 2e- Pb²+]
2 [MnO, + 8 H* + 5e¯ = Mn²+ + 4 H,O]
5 Pb+ + 2 Mn²+ + 8 H,0 =5 Pb²+ + 2 MnO, + 16 H*
E; = 1.690 V
E = 1.507 V
Determine E, AG, and K for this reaction.
cell
Transcribed Image Text:A solution containing 0.18 M Pb²+ , 1.5 × 10-6 M Pb+, 1.5 × 10-6 M Mn²+ , 0.18 M MnO, , and 0.90 M HNO, was prepared. For this solution, the balanced reduction half-reactions and overall net reaction shown can occur. 5 [Pb4+ + 2e- Pb²+] 2 [MnO, + 8 H* + 5e¯ = Mn²+ + 4 H,O] 5 Pb+ + 2 Mn²+ + 8 H,0 =5 Pb²+ + 2 MnO, + 16 H* E; = 1.690 V E = 1.507 V Determine E, AG, and K for this reaction. cell
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