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Check the given schedule for serializability:
All the methods for checking the serializability should be discussed with well drawn schedules and diagrams,
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- Implement a Restful API (with receiving data file) with all HTTP methods, using python flask framework having any scenario that contain a JSON format data of at-least 10 key-value pairs. Your solution file contains Complete code snippet of your Restful API All routes output screens (in postman tool) All server responses screens (clearly shown GET/PUT/DELETE requests and respective HTTP codes) Language : Python Software : Mentioned in Question Paste Screenshots AlsoA dispatcher of RTOS has the following three resources, A, B, and C. A has 7 instances, B has 5 instances, and C has 6 instances. At this time, the allocation, request and available map is shown in table Q1 below. a. Is this system in a safe state? Execute necessary algorithm to show your result. b. Is there a valid sequence that can work for this map? If so show it and state if it is the only one or not. c. Given the allocation table below, if PO requests 1 more resource from A and it is granted, will the system be in a safe state? d. Given the allocation table below, if C has a total of 5 slots that will leave C with only 1 available instance, will the system be in a safe state? If not, suggest a solution to overcome deadlock. Table Ql Allocation Requested Available C PO 1. 2. P1 P2 1. 1. P3 1. 2. 4 A HO 12Recall the concept of Physically Unclonable Functions, which are an importantcomponent of hardware based security. Here is a simple scenario and simple protocol usingPUFs for authenticating a tag. In the protocol below, the Reader stores ALL possiblecombinations of Challenge-Response pairs for every tag it needs to authenticate. Duringauthentication, the Reader broadcasts the ID of the tag, and a greeting (Gn ). Every tag maysee this message, but only the one with the right ID will process the message. The right tagwith the ID in the message will then feed the greeting to its PUF and compute the responseSn. The response is then sent to the Reader. This should be clear from the Figure below. Forthe next round of authenticating the same Tag, the process repeats with a new Greeting(G n+1 ). Since the Reader has the responses, authentication is straightforward. Recall thatChallenges and Responses are typically 128 or 256 bit strings for RFIDs.From the protocol, and class, it should be…
- Develop a client that takes an int value N from the command line and does an amortized plot of the cost of all operations in the style of the plots in the text for the process of generating random pairs of integers between 0 and N-1, calling connected() to determine if they are connected and then union() if not (as in our development client), looping until all sites are connected.Create a weighted quick union implementation that does not require the number of items in advance using linked lists or a resizing array. Add the newSite() method, which returns an int identification, to the API.Consider this schedule: T2:R(X), T2:W(X), T1:W(X), T1:R(Y), T1:W(Y), T2:Commit, T1:Commit Select the best correct answer about this schedule. a. Avoid cascading abort, Conflict-serializable and Serializable and Strict b. Serializable c. Conflict-serializable and Serializable d. Avoid cascading abort, Conflict-serializable, Serializable Clear my choice Consider this schedule: R2(B), W2(B), R3(C), W3(C), R3(A), W3(A), Commit3, R2(C), W2(C), Commit2, R1(A), R1(B), W1(A), W1(B), Commit1 Is this schedule conflict-serializable? Is it possible under 2PL? Is it possible under strict 2PL? a. No, Yes, No b. No, Yes, Yes c. Yes, Yes, No d. Yes, Yes, YesGiven that you have submitted many requests to a server, each with its own id (or unique identification) and priority (or priority).Requests = [(id1, p1), (id2, p2), ……, (idn, pn)], where p1 > p2 > …. > pn. Provide the best algorithm or pseudocode for dealing with all of the requests.
- A set {Po,Pi,.Pn} of waiting processes must exist such that Po is waiting for a resource held by Pi,Pi is waiting for a resource for a resource held by P2., Pn-1 is waiting for a resource held by Pn, and Pn is waiting for a resource held by PO.This condition for deadlock is referred to as a. No Preemption O b. Circular Wait Oc. Mutual Exclusion O d. Hold and Waitblockchain is a collection ofrecords (called blocks), where each block links to the previous block using cryptography. Eachblock contains cryptographic hash, timestamp and data relevant to its application. Think ofit as a distributed ledger where instead of information being stored in a database it is storedon the blockchain. Some examples of solutions that use a blockchain at its core are:1. Cryptocurrencies (however, for this project you may NOT do a cryptocurrency)2. Smart contracts3. Trading4. Supply chain management5. Anti-counterfeiting6. Healthcare7. Domain names8. Proof of existence9. Voting10. and many others! Programming Language: Java The use of third-party libraries for primary functionally is strictly prohibited, however, third party libraries can be used for other functionality such as communications and visualisation (such as normal JavaFX, JFreeChart, GraphStream, JGraphT, Yworks, JUNG or JMonkey). The use of other data structures for auxiliary operations is…don't want copy paste answer please Here is a schedule with one action missing:R1(C); W2(D); R2(B); ???; W1(A); R3(D); W2(C); W3(B)Figure out which READ actions could replace the ??? and make the schedule not conflict-serializable. Find all possible solutions.
- Correct answer will be upvoted else downvoted. Computer science. change p is composed from left to directly on the paper. First Qingshan picks an integer list x (1≤x≤n) and tells it to Daniel. From that point onward, Daniel picks another integer file y (1≤y≤n, y≠x). The game advances turn by turn and of course, Qingshan moves first. The principles follow: In case it is Qingshan's move, Qingshan should change x to such a record x′ that 1≤x′≤n, |x′−x|=1, x′≠y, and px′<px simultaneously. In case it is Daniel's move, Daniel should change y to such a record y′ that 1≤y′≤n, |y′−y|=1, y′≠x, and py′>py simultaneously. The individual who can't take her or his action loses, and different successes. You, as Qingshan's fan, are approached to compute the number of conceivable x to make Qingshan win for the situation the two players play ideally. Input The primary line contains a solitary integer n (2≤n≤105) — the length of the change. The subsequent line contains n…Part(a): What is a Deadlock? How it is detected? What are the necessary conditions for a deadlock to occur? Part(b): Suppose there are two resources available and the initial value of semaphore is set to 3.Consider a situation where P() and V() functions are called as follows. P(), P(), V(), V(), P(), P(), V(), P(), P(), V(), P(),P(),P(),V() Answer the following: 1. How many processes are sleeping on P ()?What is the value of semaphore? 2. How may processes have successfully completed their execution? 3. How many resources are available?MCQ: A set { P0, P1, Pn} of waiting processes must exist such that P0 is waiting for a resource held by P1, P1 is waiting for a resource held by P2, …, Pn-1 is waiting for a resource held by Pn, and Pn is waiting for a resource held by P0. This condition for deadlock is referred to as a. Hold and Wait b. Mutual Exclusion c. Circular Wait d. No Preemption