CE. 43mm Fry 12mm gmR 62mm gmm Amm Smin 10mm 29mm 5mm bom 5nim 2mm Fmm q WHAT iS THE DISTANCE OF THE CENTROID FROM THE X-AXIS b) WHAT IS THE DETAMCE OF THE CEMTROID FROM THE Y AX1S C WhAT IS THE INERTIA ABOUT THE XAXIS WHAT IS THE INERTIAA ABOLur THE Y-AXIS

Q: 500KN A 200mm 100mm C 45° %24

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Q: -2a 40.507 20/3 =0.50 igure shown (a=193), a. Determine the coordinates of the centroid b. Calculate…

A: A1=3a*5a3=5a2A2=122a*2a3=0.667a2A3=0.5a*0.5a=0.25a2A4=π*(0.5a)22=0.125a2xi:x1=1.5ax2=a+23*2a=2.33ax3…

Q: Length of beam=5m 6016mm 60 16 mm Section 1-11 WOZ 0.40 m-

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Q: Calculate the moment of inertia of the shaded area about the x-axis. 123 mm 36 mm Answer: Ix - i ---…

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Q: 225 mm P1=8 P2=10 M1=15 q1=18 6- 2(m) to 1(m) 4.50 (m) 1.50(m) 66 207 mm 225mm

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Q: 50 i mm 50mm a b Pu Tensio 50mm E

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Q: Activity 1. For the H- section shown, Find the value of h so that I, = Iy. 20mn 100mm h = ? 20mm…

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Q: ко 13 the shaded area in the figure shown is required to lie in the Y-axis. Deter 60mm 40mm 80mm b…

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Q: Det er m ne the moment of i nert ia of the z- section as shown in t he fi gure about its; a. cent…

A: Consider the figure.

Q: 5 kip/ft 1 ft 11 ft 30 kip-ft 11 ft Figure P-552 11 in ♫

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Q: late 1A – Double Integration Method etermine the Deflection at the midspan of AB in inches unit. Use…

A: A double integration method is one of the important methods of solving the deflection and slope of a…

Q: 1. What is the maximum beam deflection? if W-50KN/m. L-3.7m. E-52.5x10.-15.23x10 Choose the nearest…

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Q: 50mm 290mm d 230 290mm 50mm 600mm Question 3: 1x = 62 dm² a as? b) Iys? © Ix + lys?

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Q: Solve for Ix, Ix, Iy, and Iy. 20mm 2Omm Ix for circle: T*4 Ix for sem-circle: (T-4 Ix for quarter…

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Q: Deter mine the veta tron atpoint of the frame shown in figuve. Takke %3D E= 200x10 mpa / 1=3. x1o…

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Q: Conpule the centroidal distance with reupect to x-andy -ax! The hwo figue kelow- I Lem ecm

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Q: PROBLEM: Given: b = 300mm, d = 450mm, As' = 2D25mm, d' = 65mm, fc' 28MPa, and fy = 415MPA. Solve for…

A: Given data:

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Q: Given the following: b=360mm d=550mm fc'=35MPA fy=420MPA Mu=700KN-m Determine As LISE N SCR 2015 As…

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Q: 150 mm (5) 150 mm 1000 mm A, = 8622 uu OSI- unU ŞLS 650mm

A: Width ( b) = 150+150=300mm Effective depth = 575mm Factor of safety for steel =1.15 Factor of safety…

Q: ByusingAreaMomentMethod, Determinethedeflection 3mtotheleftofrollersupport. 30 kN/m 55 kN + 3 m- 9 m…

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Q: 2 L 13mm 5mm mm 3mm Select one: a. 9.95 b. 10.11 c. 7.52 d. 8.73 6mm

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Q: Calculate the moment of inertía of the shaded area about the x-axis. 76 mm 26 mm – 46 mm →-46 mm…

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Q: Given the following: b=360mm d=550mm fc'=35MPA fy=420MPA

A: The given is:b=360mmd=550mm fc'=35MPafy=420MPaMu=700kN-m

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Q: prces F so zero. 150 N -F 125 mm 30 30 130° 150 N 125mm 100mm 45 30 450 100mm F is not on its line…

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Q: 94-Det simply supported boam shown in fiy. use Pey = loo sin 4t %3D Pt) %3D m = 50 per unit length C…

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Q: 180 kN 15 kN/m B 5m- -5 m- 4m- El = constant E = 70 GPa | = 2,340 (10) mm*

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Q: 225 mm P1=8 P2=10 MJ=15 q1-18 dib 2(m) 1(m) 4.50(m) 1.50(m) 20/mm 66 225mm

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Q: A W24x103 is used as a beam that is simply supported. IT has the following Properties d= 623.10mm tw…

A: Ix = 1248.68 × 106 mm4  y = d/2 = 623.1/2 = 311.55mm  Fy =248MPa

Q: A/58 Calculate the moment of inertia of the 300 x 100-mm channel section about the centroidal…

A: Given data: Channel section= 300×100 mm Hand book Ix=6.25×106 mm4

Q: 500 N.m 100 N.m B

A: Solution

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Q: Question #02 late the Moment of Inertial (X-X & Y-Y} iKi6" Steel plate the centroid is (-0:159,…

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Q: า 130 mm- mm S: yo ++-% -20 mm -130 mm- 20 mm (106) mm4

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Q: A 10 2 Technology Driven by (nnovntion TECH ir answer in two decimal places. Units in millimeters.…

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Pressure and Stress