desired Mg mass =0.0340g "Atmospheric pressure (mmHg): 733.59 Trial 1 and Trial 2 values separated by commas: Mass of Mg (g): 0.038, 0.031 Temperature (°C): 20.2 (both trials) Vapor pressure of water (mmHg): 17.86 (both trials) Volume of gas (mL): 42.95, 35.80 need calculations for table.
desired Mg mass =0.0340g "Atmospheric pressure (mmHg): 733.59 Trial 1 and Trial 2 values separated by commas: Mass of Mg (g): 0.038, 0.031 Temperature (°C): 20.2 (both trials) Vapor pressure of water (mmHg): 17.86 (both trials) Volume of gas (mL): 42.95, 35.80 need calculations for table.
Chapter6: The States Of Matter
Section: Chapter Questions
Problem 6.103E
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Question
desired Mg mass =0.0340g
"Atmospheric pressure (mmHg): 733.59
Trial 1 and Trial 2 values separated by commas:
Mass of Mg (g): 0.038, 0.031
Temperature (°C): 20.2 (both trials)
Vapor pressure of water (mmHg): 17.86 (both trials)
Volume of gas (mL): 42.95, 35.80
need calculations for table.
Transcribed Image Text:Table 1.
Atmospheric pressure (______)
Desired mass of Mg (_____)
Mass of Mg()
Moles of Mg reacted
Moles of H₂ produced
Total pressure (
Temperature (
Vapor pressure of water (_____)
Partial pressure of H₂ (____)
Volume of gas
Experimental R (_____)
Average experimental R (______)
% Error for R
Trial 1
Trial 2
*This calculation is to be done ahead of time as part of the pre-
lab quiz. Include the calculation in your lab notebook.
*Use the average above as the "measured" value and the
accepted Rvalue (that we use in class) as the "true" value.
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