To approximate (1-1) 1/4 Lel- of (x) = x ²4 So, Let at a second order approximale-. for of (*) centered at a is 105 2 f(x) ~ f(a) + f(a) (u-a) + fill(a) (u-a) ² 21 лек azl f(~) ~ f (1) + f '(1) ('m-1) + f "(₁) (x-1) ² 21 5-3/4 (1-1). +. (-3) 15 7 / 4 (^-^)². 2 = 1 + 4 (1) ³/4 2 = 1 + + (x-1) - 323²₂ (2-1) ² कुर f (1-1) = 1.- + -1 (1-1-1)-2 (1-1-1) ² 32 21+ 1X0.1 3 x.0.01 470. 32 10240625 f'(x) = 1/4 2 ³/4 e f"(x) = -7/2274]

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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my question is for the highlighted parts, can you explain how you got the exponent -3/4 and -7/4?

To approximate (1-1) 1/4
Lel- of (x) = x ²4
So, Let at
a second order approximale-.
for of (*) centered at a is
105
2
f(x) ~ f(a) + f(a) (u-a) + fill(a) (u-a) ²
21
лек azl
f(~) ~ f (1) + f '(1) ('m-1) + f "(₁) (x-1) ²
21
5-3/4 (1-1). +. (-3) 15 7 / 4 (^-^)².
2
= 1 + 4 (1) ³/4
2
= 1 + + (x-1) - 323²₂ (2-1) ²
कुर
f (1-1) = 1.- + -1 (1-1-1)-2 (1-1-1) ²
32
21+ 1X0.1 3 x.0.01
470.
32
10240625
f'(x) = 1/4 2 ³/4 e
f"(x) = -7/2274]
Transcribed Image Text:To approximate (1-1) 1/4 Lel- of (x) = x ²4 So, Let at a second order approximale-. for of (*) centered at a is 105 2 f(x) ~ f(a) + f(a) (u-a) + fill(a) (u-a) ² 21 лек azl f(~) ~ f (1) + f '(1) ('m-1) + f "(₁) (x-1) ² 21 5-3/4 (1-1). +. (-3) 15 7 / 4 (^-^)². 2 = 1 + 4 (1) ³/4 2 = 1 + + (x-1) - 323²₂ (2-1) ² कुर f (1-1) = 1.- + -1 (1-1-1)-2 (1-1-1) ² 32 21+ 1X0.1 3 x.0.01 470. 32 10240625 f'(x) = 1/4 2 ³/4 e f"(x) = -7/2274]
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