Calculating K from equilibrium concentrations and vice versa 8. At 298 K, the equilibrium constant for the following reaction is 6.50 x 10.³. 2 NOBr(g) 2 NO(g) + Br2(g) If an equilibrium mixture of the three gases in a 10.5 L contains 9.496 mol NOBr(g) and 0.470 mol of NO, how many moles of Br2(g) are present at equilibrium?

Chemistry: The Molecular Science
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Chapter12: Chemical Equilibrium
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Calculating K from equilibrium concentrations and vice versa
8. At 298 K, the equilibrium constant for the following reaction is 6.50 x 10³.
2 NOBr(g)
2 NO(g) + Br₂(g)
If an equilibrium mixture of the three gases in a 10.5 L contains 0.496 mol NOBr(g) and
0.470 mol of NO, how many moles of Br2(g) are present at equilibrium?
Transcribed Image Text:Calculating K from equilibrium concentrations and vice versa 8. At 298 K, the equilibrium constant for the following reaction is 6.50 x 10³. 2 NOBr(g) 2 NO(g) + Br₂(g) If an equilibrium mixture of the three gases in a 10.5 L contains 0.496 mol NOBr(g) and 0.470 mol of NO, how many moles of Br2(g) are present at equilibrium?
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