Calculate the wavelength of a photon emitted when singly ionized helium (He+) transitions from the n = 3 to n = 2 state. Express answer in nm to 3 significant digits. The emitted photon has a wavelength of ____ nm. If the correct answer to the above is 656nm: A photon is emitted when doubly ionized helium (He++) recombines with an electron to form He+ in the n = 2 state. How does the wavelength of the resulting photon compare to the answer from the previous problem? A. The wavelength is longer in this case because the change in energy (ΔE) is smaller. B. The wavelength is shorter in this case because the change in energy (ΔE) is smaller. C. The wavelength is longer in this case because the change in energy (ΔE) is greater. D. The wavelength is shorter in this case because the change in energy (ΔE) is greater. E. The wavelength is the same because both cases end with He+ in the n = 2 state.
Calculate the wavelength of a photon emitted when singly ionized helium (He+) transitions from the n = 3 to n = 2 state. Express answer in nm to 3 significant digits.
The emitted photon has a wavelength of ____ nm.
If the correct answer to the above is 656nm:
A photon is emitted when doubly ionized helium (He++) recombines with an electron to form He+ in the n = 2 state. How does the wavelength of the resulting photon compare to the answer from the previous problem?
A. The wavelength is longer in this case because the change in energy (ΔE) is smaller.
B. The wavelength is shorter in this case because the change in energy (ΔE) is smaller.
C. The wavelength is longer in this case because the change in energy (ΔE) is greater.
D. The wavelength is shorter in this case because the change in energy (ΔE) is greater.
E. The wavelength is the same because both cases end with He+ in the n = 2 state.
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