Calculate the value of the rate constant for each run and calculate the average value. Indicate the units for the rate costant. Given : Rate of reaction for run 1= 1.08 x10-6 M/s Rate law for Run 1 : 1.08 x10-6 M/s = k[0.00125 M]x[0.0088 M]y Eqn 1 Rate of reaction for run 2= 1.58 x10-6 M/s Rate law for Run 2 : 1.58 x10-6 M/s = k[0.0025 M]x[0.0088 M]y Eqn 2 Rate of reaction for run 3 = 1.99 x10-6 M/s Rate law for Run 3 : 1.99 x10-6 M/s = k[0.00125 M]x[0.0176 M]y Eqn 3
Calculate the value of the rate constant for each run and calculate the average value. Indicate the units for the rate costant. Given : Rate of reaction for run 1= 1.08 x10-6 M/s Rate law for Run 1 : 1.08 x10-6 M/s = k[0.00125 M]x[0.0088 M]y Eqn 1 Rate of reaction for run 2= 1.58 x10-6 M/s Rate law for Run 2 : 1.58 x10-6 M/s = k[0.0025 M]x[0.0088 M]y Eqn 2 Rate of reaction for run 3 = 1.99 x10-6 M/s Rate law for Run 3 : 1.99 x10-6 M/s = k[0.00125 M]x[0.0176 M]y Eqn 3
Chemistry by OpenStax (2015-05-04)
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Chapter12: Kinetics
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Question
Calculate the value of the rate constant for each run and calculate the average value. Indicate the units for the rate costant. Given :
Rate law for Run 1 : 1.08 x10-6 M/s = k[0.00125 M]x[0.0088 M]y Eqn 1
Rate of reaction for run 2= 1.58 x10-6 M/s
Rate law for Run 2 : 1.58 x10-6 M/s = k[0.0025 M]x[0.0088 M]y Eqn 2
Rate of reaction for run 3 = 1.99 x10-6 M/s
Rate law for Run 3 : 1.99 x10-6 M/s = k[0.00125 M]x[0.0176 M]y Eqn 3
![兴 兴
Mass of potassium iodide used
O.alg
Mass of sodium thiosulfate pentahydrate used
20.1159
Volume of 30% hydrogen peroxide
-2ml
6.0025x 2so
Part A.Rate law
33
3 =
vi/20 x30
LUTED
0.00A Sx250:
1000
Temperature
vi=(3.20/30- - 2mu
Run #1
Run #2
Run #3
Time until permanent blue color appears
||门
1.060-158*
- 99 x10
Mis
Rate of reaction
Rate law
Rate constant
Femperature of solution
0.025
-0.0a5 mo
mol Icx (son Cx/100mL
l)LX0.05OL
1.X0.050L
proj
=0.00128 mol
000125mol x lbb0gmol
al9
22 - 5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5656bf79-0e9e-499f-b5be-5c0fd163f502%2F4ffbb68f-ec4e-450d-80ec-e39305903c06%2Fyj7f3pb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:兴 兴
Mass of potassium iodide used
O.alg
Mass of sodium thiosulfate pentahydrate used
20.1159
Volume of 30% hydrogen peroxide
-2ml
6.0025x 2so
Part A.Rate law
33
3 =
vi/20 x30
LUTED
0.00A Sx250:
1000
Temperature
vi=(3.20/30- - 2mu
Run #1
Run #2
Run #3
Time until permanent blue color appears
||门
1.060-158*
- 99 x10
Mis
Rate of reaction
Rate law
Rate constant
Femperature of solution
0.025
-0.0a5 mo
mol Icx (son Cx/100mL
l)LX0.05OL
1.X0.050L
proj
=0.00128 mol
000125mol x lbb0gmol
al9
22 - 5
![](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5656bf79-0e9e-499f-b5be-5c0fd163f502%2F4ffbb68f-ec4e-450d-80ec-e39305903c06%2Fk1yl9o.jpeg&w=3840&q=75)
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