A solution containing 0.15 M Pb² +, 1.5 × 10¯6 M Pb¹+, 1.5 × 10¯6 M Mn² +, 0.15 M MnO4, and 0.85 M HNO3 was prepared.For this solution, the balanced reduction half-reactions and overall net reaction shown can occur.4+5 [Pb+ 2 e¯ = Pb²+]2 [MnO + 8 H+ + 5 e¯ ⇒ Mn² + + 4H₂O]45 Pb+ + + 2 Mn² + + 8 H₂O = 5 Pb²+ + 2 MnO² + 16H+EtE = 1.507 V= 1.690 V Calculate the value for the cell potential, Ecell, and the free energy, AG, for the given conditions.Ecell =AG=Calculate the value of Ecell for this system at equilibrium.Ecell =Determine the pH at which the given concentrations of Pb²+, Pb4 +, Mn² +, and MnO would be at equilibrium.pH=VJV

The half-reactions are: Oxidation half-reaction(Anode): 2Mn2+ + 8H2O → 2MnO4- + 16H+ + 10e- ;…

Calculate the value for the cell potential, Ecell, and the free energy, AG, for the given conditions. Ecell = AG= Calculate the value of Ecell for this system at equilibrium. Ecell = Determine the pH at which the given concentrations of Pb²+, Pb4+, Mn²+, and MnO would be at equilibrium. pH = V J V

Calculate the value for the cell potential, Ecell, and the free energy, AG, for the given conditions. Ecell = AG= Calculate the value of Ecell for this system at equilibrium. Ecell = Determine the pH at which the given concentrations of Pb²+, Pb4+, Mn²+, and MnO would be at equilibrium. pH = V J V

Chemistry & Chemical Reactivity

9th Edition

ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter21: The Chemistry Of The Main Group Elements

Section: Chapter Questions

Problem 109SCQ

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