Calculate the standard enthalpy of formation of the M2O(s) metal oxide (AH+ in kJ/mol) using the following data: Bond dissociation enthalpy of O2(g) = +498 kJ/mol First electron affinity of O = -141 kJ/mol Second electron affinity of O = +744 kJ/mol Enthalpy of sublimation of M = + 116 kJ/mol First ionization energy of M = + 463 kJ/mol Lattice enthalpy of M2O(s) = -2248 kJ/mol Refer to sections 9.4 and 9.5 in the textbook for definitions of ionization energy and electron affinity. Do not use scientific notation for your answer. Do not enter units. Your Answer:
Calculate the standard enthalpy of formation of the M2O(s) metal oxide (AH+ in kJ/mol) using the following data: Bond dissociation enthalpy of O2(g) = +498 kJ/mol First electron affinity of O = -141 kJ/mol Second electron affinity of O = +744 kJ/mol Enthalpy of sublimation of M = + 116 kJ/mol First ionization energy of M = + 463 kJ/mol Lattice enthalpy of M2O(s) = -2248 kJ/mol Refer to sections 9.4 and 9.5 in the textbook for definitions of ionization energy and electron affinity. Do not use scientific notation for your answer. Do not enter units. Your Answer:
Chemistry & Chemical Reactivity
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ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter8: Bonding And Molecular Structure
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Problem 56PS: Oxygen atoms can combine with ozone to form oxygen: O3(g) + O(g) 2 O2(g) rH = 392 kJ/mol-rxn Using...
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Transcribed Image Text:Calculate the standard enthalpy of formation of the M2O(s) metal oxide (AH+ in
kJ/mol) using the following data:
Bond dissociation enthalpy of O2(g) = +498 kJ/mol
First electron affinity of O = -141 kJ/mol
Second electron affinity of O = +744 kJ/mol
Enthalpy of sublimation of M + 116 kJ/mol
First ionization energy of M = + 463 kJ/mol
Lattice enthalpy of M₂O(s) = -2248 kJ/mol
Refer to sections 9.4 and 9.5 in the textbook for definitions of ionization energy and
electron affinity. Do not use scientific notation for your answer. Do not enter units.
Your Answer:
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