Calculate the pressure drop for a straight pipe of length L 40m, the data for this problem is given to you below: Pipe diameter D=0.01m • Flow velocity v=1.20 m/s Pipe absolute roughness €=0.00003 m Pipe length, L= 40m Dynamic viscosity=0.000354 Pa.s (dynamic viscosity of water at 80degC) Fluid density=971.79 kg/m^3 • Pressure at pipe entry, P1=1,535,922 Pa Pipe inclination =0.03 radians, the conversion factor between radians and degrees is 1 rad =57.29° • Assume acceleration of gravity 9.80 8² ● ● ● D=0.01m P1 ΔΡ =? e inclination P2 Flow direction indicated by blue arrow

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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I have attached the given moody diagram in this question, how do I complete this question accuractely?

2hDg
LV²
Darcy-Weisbach friction factor f =
0.00
10-¹
9
8
7
6
5.5
5
45
3.5
3
2.5
2
18
1.6
1.4
12
102
9
8
91
Laminar
flow
92
Critical
zone
Material
Riveted steel
Concrete
D.4 0.0 0.5
Wood stave
Cast Iron
Galvanized Iron
Asphalted cast Iron
Commercial steel
Drawn tubing
Fluid at 20°C
Water
Air (101.325 kPa)
□
ID
e (mm)
0.9-9
0.3-3
0.18-0.9
0.25
0.15
0.12
0.046
0.0015
v (m²/s)
TTT
Transition zone
1.003e-006
1.511e-005
Latitude (WGS84) g(m/s)
0.0 Sea level 9.78033
45.5 Standard 9.80665
90.0" Sea level 9.83219
i
6 78 10
2 3 4 5 6 7 8 10*
Moody Diagram
40
80
VD for water at 20°C (V in m/s, D in cm)
10
20
I
40 eo
VD for atmospheric air at 20°C
200
GOD
1000
100
Smooth pipes, r-o
1NT-2 log(RF)-0.8)
Hagen-Polsseuille equation
A ≤ 2300, 1-64/R
Colebrook equation, ♬ ≥ 2300
1Nr-2 log(r/3.7 +2.51/(√))
Continuity equation, Q - AV
A-D²14, V-4Q/(xD²)
2 3 4 5 6 7 8 10³
Reynolds number R =
400
2
VD
V
100
2000
r-5e-006
200
4000
400
Complete turbulence, rough pipes, R3500/r, 1/f-1.14-2 logr
eaco
+
3 4 5 6 7 8 10⁰
(V in m/s, Din m, v in m/s)
r-1e-006
pa
IL
10000
1000
2 3 4 5 6 7 8 107
20000
2000
4000
40000 0000
0000
10000
TI
1 DODOO
0.07
0.06
0.05
0.045
0.04
0.035
0.03
0.025
0.02
0.0175
0.015
0.0125 O
0.01
0.008
0.006
0.002
0.0015
0.004 ||
0.003
0.001
0.0008
0.0006
0.0004
0.0002
0.0001
WID
5e-005
Relative roughness r= ( in mm, D in mm)
2e-005
1e-005
2
3 4 5 6 7 8 10"
Metzger & Willard, Inc.
http://www.metzgerwillard.com
Transcribed Image Text:2hDg LV² Darcy-Weisbach friction factor f = 0.00 10-¹ 9 8 7 6 5.5 5 45 3.5 3 2.5 2 18 1.6 1.4 12 102 9 8 91 Laminar flow 92 Critical zone Material Riveted steel Concrete D.4 0.0 0.5 Wood stave Cast Iron Galvanized Iron Asphalted cast Iron Commercial steel Drawn tubing Fluid at 20°C Water Air (101.325 kPa) □ ID e (mm) 0.9-9 0.3-3 0.18-0.9 0.25 0.15 0.12 0.046 0.0015 v (m²/s) TTT Transition zone 1.003e-006 1.511e-005 Latitude (WGS84) g(m/s) 0.0 Sea level 9.78033 45.5 Standard 9.80665 90.0" Sea level 9.83219 i 6 78 10 2 3 4 5 6 7 8 10* Moody Diagram 40 80 VD for water at 20°C (V in m/s, D in cm) 10 20 I 40 eo VD for atmospheric air at 20°C 200 GOD 1000 100 Smooth pipes, r-o 1NT-2 log(RF)-0.8) Hagen-Polsseuille equation A ≤ 2300, 1-64/R Colebrook equation, ♬ ≥ 2300 1Nr-2 log(r/3.7 +2.51/(√)) Continuity equation, Q - AV A-D²14, V-4Q/(xD²) 2 3 4 5 6 7 8 10³ Reynolds number R = 400 2 VD V 100 2000 r-5e-006 200 4000 400 Complete turbulence, rough pipes, R3500/r, 1/f-1.14-2 logr eaco + 3 4 5 6 7 8 10⁰ (V in m/s, Din m, v in m/s) r-1e-006 pa IL 10000 1000 2 3 4 5 6 7 8 107 20000 2000 4000 40000 0000 0000 10000 TI 1 DODOO 0.07 0.06 0.05 0.045 0.04 0.035 0.03 0.025 0.02 0.0175 0.015 0.0125 O 0.01 0.008 0.006 0.002 0.0015 0.004 || 0.003 0.001 0.0008 0.0006 0.0004 0.0002 0.0001 WID 5e-005 Relative roughness r= ( in mm, D in mm) 2e-005 1e-005 2 3 4 5 6 7 8 10" Metzger & Willard, Inc. http://www.metzgerwillard.com
Calculate the pressure drop for a straight pipe of length L 40m, the data for this
problem is given to you below:
● Pipe diameter D=0.01m
• Flow velocity v=1.20 m/s
Pipe absolute roughness €=0.00003 m
Pipe length, L= 40m
Dynamic viscosity=0.000354 Pa.s (dynamic viscosity of water at 80degC)
• Fluid density=971.79 kg/m^3
• Pressure at pipe entry, P1=1,535,922 Pa
• Pipe inclination 0 =0.03 radians, the conversion factor between radians and
degrees is 1 rad =57.29°
• Assume acceleration of gravity 9.80
D=0.01m
P1
m
ΔΡ =?
L
0 inclination
P2
Flow direction indicated
by blue arrow
Z
Transcribed Image Text:Calculate the pressure drop for a straight pipe of length L 40m, the data for this problem is given to you below: ● Pipe diameter D=0.01m • Flow velocity v=1.20 m/s Pipe absolute roughness €=0.00003 m Pipe length, L= 40m Dynamic viscosity=0.000354 Pa.s (dynamic viscosity of water at 80degC) • Fluid density=971.79 kg/m^3 • Pressure at pipe entry, P1=1,535,922 Pa • Pipe inclination 0 =0.03 radians, the conversion factor between radians and degrees is 1 rad =57.29° • Assume acceleration of gravity 9.80 D=0.01m P1 m ΔΡ =? L 0 inclination P2 Flow direction indicated by blue arrow Z
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