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Dielectric Constant Of Water
Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.
Electrostatic Potential and Capacitance
An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
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- PROBLEM-SOLVING: Given the following situations below, read thoroughly the problem and identify what is asked. Provide your answers and solutions either through photos of your calculations or by typing on the provided field with the final answer highlighted. An electrical wire is rated up to 8A when it was used to pass 300c of charge for 12s. W the rated current of the electrical wire be enough to the actual electrical demand? What do you think will happen to the wire? Provide a short statement and support it with computations.Learning Task 5: Solve the following problems. 1. A charge of 2 µC is 0.5m from a charge of 3µC. Find the electric force. 2. Two equal charges are located 1m from each other. The force acting between them is 2N. How many Coulombs is each charge? 3. How far apart must two electrons be if the force between them is 1x 10-12N? 4. A charge of 3µC is used to test the electric field of a central charge of 6C that causes a force of 800N. What is the magnitude of the electric field? 5. What is the electric flux when a uniform electric field of 9000 N/C passes through a flat square area of 2m² at a 30° angle?Use the attached diagram to answer the following questions. 1. At P the electric field is zero. Explain how the electric field can be zero. 2. The magnitude of the charge on X is Q and that on Y is q. The distance between X and Y is 0.600 m. The distance between P and Y is 0.820 m.Determine, to one significant figure, the ratio Q/q.
- III. LEARNING TASKS: A. Practice Task 1. Instruction: Evaluate the diagrams below. If the diagram is CORRECT, smile first and draw a happy face inside the box. If you think the diagram is INCORRECT, draw a sad face () inside the box. Then, indicate your reason on the space provided. 1. Static electricity Electrostatic Why do you say so? 2. > Why do you say so? Uncharged object 4. 3. > Why do you say so? Electron 5. Proton > Why do you say so? Attraction Why do you say so? Neutral body 6 Electricity at rest Equal number of protons and electrons Positively charged :: Negatively charged RepulsionThis is not a graded question. Answer all questions below. A. Calculate the electric field experienced by a negative test charge given thw following conditions: 1. Source charge: +5.03 × 10-4 C Distancefromsourcecharge: 2.33 × 10-5 m 2. Source charge: -4.33 × 10-12 C Distance from source charge: 4.6 × 10-19 m 3. Source charge: +6.78 × 10-15 C Distance from source charge: 7.9 × 10-19 m B. Compute the electronics force experienced by -4.33 × 10 kC charge from the following electric fields: 1. Ē> = 5,465 N/C 2. Ē> = 9.5 × 1015 N/C 3. Ē> = 8.97 × 1024 N/CLearning Task 2: Solve Me! Directions: Sketch the diagram for each item and solve what is being asked. 1. Three capacitors with individual capacitances of 2 uF, 5 uF, and 10 uF respectively are connected in series with a 12V battery. What are the total capacitance and total charge in the network? 2. Same capacitors in number 1 connected in a parallel. If the combined charge in the network is 50 µC, what are the total voltage and total capacitance in the network? 3. A series combination of two uncharged capacitors are connected to a 15-V battery, 300 pJ of energy is drawn from the battery. If one of the capacitors has a capacitance of 5.0 pF, what is the capacitance of the other? Learning Task 3 Series-Parallel Capacitor Four capacitors are oconnected as shown in the figure below. Determine the following: A. Total Capacitance (Cr) B. Total Charge (Qr) C. Individual Charges (Q, Q, Qs, Qa) D. Voltage drop in each capacitor (V1, Va. Va, Va) C, = 45 nF C2 = 5 µF C = 2.5 uF Vr = 30 V C, = 30…
- Capacitance, Charge and Voltage: Q = CV 1. Click the Reset Button on the bottom right of the PHET simulation. 2. CHECK Plate Charges and Bar Graphs boxes in the upper right so your display resembles the graph below. 3. SET the Plate Area to 200 mm² and the Separation to 4.0 mm. Capactance Tup Pate Charge oc Sured Energy Pu Charges r Graphs O e Fd Cument Direction 1500 V 4. Connect the voltmeter across the capacitor by placing the red on the top plate and black on bottom. If the voltmeter reads a negative, switch the red and black. 5. Set the battery Voltage to 0.25 V. Record the measured plate charge, Q. 6. Repeat Step 5 for each Voltage in Table 3. Table 3: Charge and Voltage Voltage |(V) Plate Charge |(pC) 0.25 V 0.50 V 0.75 V 1.00 V 1.25 V 1.50 VActivity No. 2 Answer the following questions involving charge interactions. 2. A negatively charged balloon is brought near a neutral conducting sphere as shown below. As it approaches, charge within the sphere will distribute 1. Jin is investigating the charge on several objects and makes the following findings. Jin knows that object A is negatively charged itself in a very specific manner. Which one of the diagrams below properly depicts the distribution of charge in the sphere? and object B is electrically neutral. What can Jin definitively conclude about the charge on objects C, D, E, and F? Object C Object D Object E attracts D repels F Object F attracts B repels C attracts A Solution and Answer: d. Encircle the letter of the correct answer. PURR: .Check your understanding A. Solve the problems below. You are required to show the proper solution with the final answer written inside a box. Make sure to put the final unit of measurement. 1. If in the process of rubbing the lenses of the eyeglasses, 6.28 x 10 10 electrons were transferred, a. what is the charge of the lenses and the nylon cloth? b. what is the change in their masses? CS Scanned with CamScanner
- TASKS: Read and analyze the problems. Answer the practice and challenge questions. Write your solution on the space provided. A parallel plate capacitor consists of two metal plates, a Geiger tube, whose radius of 10.0 cm and a each of area of and measurements are 0.200 concentric metal spherical You are shown the inside of A hollow metal sphere has separated thick air, can hold mm in radius and 12.0 cm, shell has an inside radius of a charge of magnitude 0 = in length. The outer surface 10.5 cm. 1.00 x 10" C on each plate. of the tube is a conducting cylindrical shell that has a radius of 1.50 cm. Practice: What is the capacitance of this device? capacitance of your tube Practice: Calculate the Practice: What is the capacitance of this two- sphere system? Challenge: What is the potential difference (V) between the plates? Challenge: Calculate the Challenge: What is the value of the linear charge energy stored, (U) in Joules (Q) on the wire when the in the capacitor ifQ = 5.00…Derived the following formula according to what is being asked. A. Get the value of Q from the given formula below. Q B. If E= Fe/qand F= q1q2/ r2, what would be the value of E, if you will expand it using the given value of force from Coulomb's formula? c. Obtain the value of E from the (B) problem and the area of a sphere, which represents A in the given formula, and then expand the formula of 0=E-A. D. Obtain the value of E from the (B) problem and the area of a cylinder, which represents A in the given formula, and then expand the formula of 0=E-A.Part A The lines show the equipotential contours in the plane of three point charges, Q1, Q2, and Q3. The values of the potentials are in kV as indicated for the +5, 0, and -5 kV contours. The positions of the charges are indicated by the dots. cm 1 Q₁. Volts 2 +5 Q3 The letters are on the equipotential contours. Q₂ # m