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Calculate the ∆Hof of C6H12O6(s) from the following data:  ∆H combustion of C6H12O6(s) = -2816kJ/mol ∆Hof of CO2 (g) = -393.5 kJ/mol ∆Hof of H2O(l) = -285.9 kJ/mol   Equation: C6H12O6(s) + O2(g) →    CO2(g) + H2O(g)

Calculate the ∆Hof of C6H12O6(s) from the following data:  ∆H combustion of C6H12O6(s) = -2816kJ/mol ∆Hof of CO2 (g) = -393.5 kJ/mol ∆Hof of H2O(l) = -285.9 kJ/mol   Equation: C6H12O6(s) + O2(g) →    CO2(g) + H2O(g)

Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter7: Chemical Energy
Section: Chapter Questions
Problem 67E: The enthalpy of combustion of solid carbon to form carbon dioxide is 393.7 KJ/mol carbon, and the...
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Calculate the ∆Hof of C6H12O6(s) from the following data: 

∆H combustion of C6H12O6(s) = -2816kJ/mol

∆Hof of CO2 (g) = -393.5 kJ/mol

∆Hof of H2O(l) = -285.9 kJ/mol

 

Equation: C6H12O6(s) + O2(g) →    CO2(g) + H2O(g)

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