C++ Transform this function into an iterative one using the transformation for tail-recursive functions int randomSelect (int A[], int size) { if (size == 0) return -1; else if (size == else 1) return A[0]; else if (rand() % 2 == 0) return A[size-1]; return randomSelect (A, size-1);
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C++ Help
![C++
Transform this function into an iterative one using the transformation for tail-recursive functions
int randomSelect (int A[], int size)
{
}
if (size
= 0)
return -1;
else if (size
==
else
==
1)
return A[0];
else if (rand() % 2 == 0)
return A[size-1];
return randomSelect(A, size-1);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa15a3309-6b07-4866-b3be-9f0895e56cbb%2F88166585-d88f-4294-b60f-3beabf33eed3%2Fyf9ejbo_processed.jpeg&w=3840&q=75)
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- Consider the following function: void fun_with_recursion(int x) { printf("%i\n", x); fun_with_recursion(x + 1); } What will happen when this function is called by passing it the value 0?7. Convert this iterative function into recursive function. [s] int factorial (int num){ int answer=1; for(int t = 1; t>num; t++) { answer answer * (t); return (answer); }java C++ Ackermann’s FunctionAckermann’s Function is a recursive mathematical algorithm that can be used to test how well a computer performs recursion. Write a function A(m, n) that solves Ackermann’s Function. Use the following logic in your function:If m = 0 then return n + 1If n = 0 then return A(m−1, 1) Otherwise, return A(m−1, A(m, n−1))Test your function in a driver program that displays the following values:A(0, 0) A(0, 1) A(1, 1) A(1, 2) A(1, 3) A(2, 2) A(3, 2) SAMPLE RUN #0: ./AckermannRF Hide Invisibles Highlight: Show Highlighted Only The·value·of·A(0,·0)=·1↵ The·value·of·A(0,·1)=·2↵ The·value·of·A(1,·1)=·3↵ The·value·of·A(1,·2)=·4↵ The·value·of·A(1,·3)=·5↵ The·value·of·A(2,·2)=·7↵ The·value·of·A(3,·2)=·29↵
- CodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/2021Write a recursive function called that takes a string of single names separated by spaces and prints out all possible combinations (permutations), each combination on a new line. When the input is: Alice Bob Charlie then the output is: Alice Bob Charlie Alice Charlie Bob Bob Alice Charlie Bob Charlie Alice Charlie Alice Bob Charlie Bob Alice Here is my original code that needs to be fixed: def all_permutations(permList, nameList): # TODO: Implement method to create and output all permutations of the list of names. if nameList == len(permList) - 1: return nameList else: for x in range(permList, len(nameList)): permList[nameList], permList[x] = permList[x], permList[name_List] return all_permutations(permList, nameList + 1) permList[nameList], permList[x] = permList[x], permList[name_List] if __name__ == "main": nameList = input().split(' ') permList = [] all_permutations(permList, nameList)For function addOdd(n) write the missing recursive call. This function should return the sum of all postive odd numbers less than or equal to n. Examples: addOdd(1) -> 1addOdd(2) -> 1addOdd(3) -> 4addOdd(7) -> 16 public int addOdd(int n) { if (n <= 0) { return 0; } if (n % 2 != 0) { // Odd value return <<Missing a Recursive call>> } else { // Even value return addOdd(n - 1); }}
- Which is the base case of the following recursion function: def mult3(n): if n == 1: return 3 else: return mult3(n-1) + 3 else n == 1 mult3(n) return mult3(n-1) + 3Exercise 1: The number of combinations CR represents the number of subsets of cardi- nal p of a set of cardinal n. It is defined by C = 1 if p = 0 or if p = n, and by C = C+ C in the general case. An interesting property to nxC calculate the combinations is: C : Write the recursive function to solve this problem.Write a recursive function (no auxiliary functions, for/while loops, STL containers or functions, static/global variables) bool mirrorMirrorOnTheWall(string n); Given a string, recursively determine if the string is the same forwards and backwards. mirrorMirrorOnTheWall(""); mirrorMirrorOnTheWall("a"); mirrorMirrorOnTheWall("mirror"); // returns false mirrorMirrorOnTheWall("racecar"); // returns true // returns true // returns true Edit View Insert Format Tools Table 12pt v Paragraph v BIU ...
- Please IN C++ Write the simplest program that will demonstrate iteration vs recursion using the following guidelines - Write two primary helper functions - one iterative (IsArrayPrimeIter) and one recursive (IsArrayPrimeRecur) - each of which Takes an array of integers and its size as input params and returns a bool such that 'true' ==> all elements of the array are prime, so the array is prime, 'false' ==> at least one element in array is not prime, so array is not prime. Print out a message "Entering <function_name>" as the first executed statement of each function. Perform the code to test whether every element of the array is a Prime number. Print out a message "Leaving <function_name>" as the last executed statement before returning from the function. Remember - there will be nested loops for the iterative function and there can be no loops at all in the recursive function. For the recursive function - define one other helper function (IsPrimeRecur) which…A/ find code optimization method to this code and then find type to this code 1- For(i=1;iWrite a recursive function maxArrayList (ArrayList A, int first, int last) that receives an ArrayList A, first index, last index and returns the largest integer number in the ArrayList A public static int maxArrayList (ArrayList A, int item) that receives an ArrayList A, an integer called item and returns the number of times that item occurs in A public static int searchArrayList (ArrayListSEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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