Please answer the ff: ty! Step 3(c) By how much can we expect 28-day strength to change when accelerated strength increases by 80 psi?When accelerated strength increases by 1 psi, the expected change in 28-day strength is ₁ = 1.2. Therefore, when accelerated strength increases by 2 psi, the expected change in 28-day strength (inpounds per square inch) is 20₁psi.We can follow this model to see that the expected change in 28-day strength is equal to P₁ = 1.2 times the increase in accelerated strength.Therefore, the expected change in 28-day strength (in pounds per square inch) for an increase of 80 psi in accelerated strength is equal to 1.2=Submit Skip (you cannot come back)orpsi.

It is given that the regression equation is y = 1820 + 1.2x

(c) By how much can we expect 28-day strength to change when accelerated strength increases by 80 psi? When accelerated strength increases by 1 psi, the expected change in 28-day strength is ₁ = 1.2. Therefore, when accelerated strength increases by 2 psi, the expected change in 28-day strength (in pounds per square inch) is 2₁ = psi. We can follow this model to see that the expected change in 28-day strength is equal to ₁ = 1.2 times the increase in accelerated strength. Therefore, the expected change in 28-day strength (in pounds per square inch) for an increase of 80 psi in accelerated strength is equal to 1.2([ Submit Skip (you cannot come back) psi.

(c) By how much can we expect 28-day strength to change when accelerated strength increases by 80 psi? When accelerated strength increases by 1 psi, the expected change in 28-day strength is ₁ = 1.2. Therefore, when accelerated strength increases by 2 psi, the expected change in 28-day strength (in pounds per square inch) is 2₁ = psi. We can follow this model to see that the expected change in 28-day strength is equal to ₁ = 1.2 times the increase in accelerated strength. Therefore, the expected change in 28-day strength (in pounds per square inch) for an increase of 80 psi in accelerated strength is equal to 1.2([ Submit Skip (you cannot come back) psi.

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter6: Vector Spaces

Section6.7: Applications

Problem 14EQ

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