boxes move under the effect of the applied force F = 40 N. Coefficient of friction between the surfaces is 0.3. Masses m1 = 4 kg and m2 = 1.5 kg. Angle θ = 31°. Solve the acceleration of the boxes. Solve the velocity of the box after 5 sec. Solve the tension on the rope

Physics for Scientists and Engineers
10th Edition
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Physics And Measurement
Section: Chapter Questions
Problem 26P: Review. Prove that one solution of the equation 2.00x43.00x3+5.00x=70.0 is x = 2.22.
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Two boxes move under the effect of the applied force F = 40 N. Coefficient of friction between the surfaces is 0.3. Masses m1 = 4 kg and m2 = 1.5 kg. Angle θ = 31°.

  1. Solve the acceleration of the boxes.

  2. Solve the velocity of the box after 5 sec.

  3. Solve the tension on the rope.

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mi
Transcribed Image Text:m2 mi
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