Blocks m = 4.0 kg and m2 = 1.0 kg are connected by a thin, light cord which is draped over a light pulley so that mass u= 0 m¡ is hanging over the edge of the pulley as shown. The surface between m2 and the table is essentially frictionless. What is the acceleration (in m/s²) of the blocks? |m2 mi (Take g=10 m/s²) O 4 O 2 O 10 O 6
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- Q1: An object of mass m1=5kg placed on frictionless horizontal table is connected to a string that passes over a pulley and then is fastened to a hanging object of mass m2 = (a) Draw free-body diagrams of both objects. (b) Find the magnitude of the acceleration of the objects. (c) Find the tension in the string. 9kg M (10 marks) M2The crate with a mass of 80 kg is being towed by a chain which is directed at 20°. Find the crate acceleration in t = 2 s if the force P = 90t² N, normal force of 661.67 N and the coefficient of kinetic friction = 0.3. O a. 7.51 m/s² O b. 1.75 m/s² O c. 3.50 m/s² d. 2.44 m/s² 20° PQ1. m-1 kg m,=4 kg The mechanism set up with m,, m, and weightless pulleys is as shown in the figure. Then, the masses are released. Static and kinetic friction between the inclined plane and m, are 0.6 and 0.5 respectively. What are the accelerations of m, and m,? (g = 10 m / s². Frictions and mass of the pulley are ignored.) Q2. 300 m/s .*........ yatay 100 m/s 320 m x=? A plane is flying horizontally at an altitude of 320 m with 300 m/s speed. It launches its bomb with 100 m/s speed relative to the plane as shown. How many meters away from the castle should the plane launch its bomb to hit the castle. (g=10 m/s², sin370=0.6; cos37°=0.8) Q3. 2 kg The object in the frictionless cone in the figure is making a uniform circular motion. Calculate, a) the normal force that the cone exerts on the object, b) centripetal force applied to the body, c) Find the speed of the object.
- A cord passing over a pulley connects two masses, as shown, where m1 = 3.80 kg and m2 = 7.20 kg. The system accelerates with a magnitude of 0.94 m/s2. The coefficient of kinetic friction between the masses and the incline is the same for both masses. Assume the pulley is frictionless, and the cord is massless. (Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign.) What is the tension (in N) in the cord?A heavy cabinet with a mass of 135kg is transported on the truck platform. Assume that the friction between the cabinet and the platform is so great that the cabinet cannot slip, but can instead tip over. The dimensions shown in the cabinet figure are hG = 1.8m, xG = 1.0m and b = 3.4m. How high can the maximum acceleration of the truck to the right be without the cabinet tipping over? What is the angular acceleration of the cabinet in the situation under considerationFor the delivery truck shown: The mass of the truck is 4000 kg. The horizontal distance from the rear tires to the center of mass, G, is L1 = 3 m The vertical distance from the ground to G is d = 3m The horizontal distance from the rear tires to the front tires is L2 = 5 m. d The delivery truck is traveling at 20 m/s when the brakes are applied. The truck skids to a stop, so that the friction force is applied to the tires by the road.* The coefficient dynamic friction is uk = 0.60 *If it did not skid, then the friction force would be between the brake pads and the brake disc, which would be above the road. Calculate the distance that the truck travels before it stops. Use Σ MA = Ia + d x m*a for the following: 'O' Calculate the left side of this equation: Σ MA G L1 → L2 Calculate the right side of this equation: I*α + d x m*a d+ x m*a is from r x m*a (cross product), so, determine the sign by considering the cross product. Set the left and right right sides equal to each other and…
- weighs 60 N on Earth. (3). A system consists of a pulley (vertical wheel) that is only allowed to rotate (spin). A cord is passed over the pulley and at each end there is a mass attached to the end of the cord. The mass attached on the left is m, =0.6 kg and at the right the mass is m2 = 0.8 kg. a) Calculate both the Tension in the cord and the acceleration of the system. b) What are the accelerations of both masses, if you were to cut the cord? Neglect the friction between cord and wheel,According to the figure where a mass M = z/100 kg on the frictionless floor is being pushed by horizontal m force F. A mass m = 3.00 kg is placed on top of M F M and the coefficient of static and kinetic friction between the surfaces are 0.500 and 0.300, respectively. Find the maximum value of F (in Newton) which allows mass m to move with mass M without slipping. (Use g = 9.80 m/s2)In the adjacent figure, two masses connected by a rope (mass ignorant) pass around the pulley of torque I. Find the acceleration of the two masses while ignoring the friction around the axis of the pulley's rotations. Then discuss the results when mi =Mz |3D missMz M2. M, =0
- A uniform rod of mass M = 2.3 kg and length L = 0.2 m, lying on a frictionless horizontal plane, is free to pivot about a vertical axis through one end, as shown. The moment of inertia of the rod about this axis is given by 1/3 ML2. If a force F = 7 N, q = 47° acts as shown, what is the resulting angular acceleration (in rad/s2) about the pivot point?1. A block of mass m slides down on the surface of a wedge of mass M (see figure below). If there are no frictions between the block and the wedge, and between the wedge and the table, find the acceleration of the wedge, the normal force between the block and the wedge, and the acceleration of m relative to the wedge. Discuss your results in the limit of m<The lower block of mass m2 = 3.2 kg is pulled on by a rope with a tension force of 28 N. The upper block has mass m1 = 1.8 kg. The coefficient of kinetic friction between the lower block and the surface is 0.32. The coefficient of kinetic friction between the lower block and the upper block is also 0.32. What is the acceleration of the 3.2 kg block?SEE MORE QUESTIONS