Binary Heaps ) ( No code needed use trees represntation ) Sort the following array using heap sort algorithm. [ 77 , 45 , 38 , 28 , 12 , 17 , 9 ]
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- 5) Sort the list A[]={ 20, 13,4, 34, 5, 15, 90, 100, 75, 1} by application of Heap Sort (Insert the elements of the array into a Minheap one by one using the Insert function and then delete them from the Minheap into the same array using the Delete function.) Just show the steps and no need to write any algorithm.()8. integer array nums and an integer k, return the length of the shortest non-empty subarray of nums with a sum of at least k. If there is no such subarray, return -1. A subarray is a contiguous part of an array. Example 1: Input: nums = [1], k = 1 Output: 1 Example 2: Input: nums = [1,2], k = 4 Output: -1 Example 3: Input: nums = [2,-1,2], k = 3 Output: 3.CH:7 assignment: write an Using: algorithm Blowering 432, 8, 530, 90, 88, 231, 11, 45, 677, 199. (1) insertion sort (11) to sort following: eachy. Steps to sort Sort Merye (11) Quick Sort (c) Heap sort (V) Radix 1 (vi) Shell sort. 11
- a) Consider an unsorted array of elements {25, 17, 36, 2, 3, 100, 1, 19, 7}: iii) Show the steps to search for 25 in the above sequence using binary search algorithm.18. (rac 18, Trace bucket sort algorithm as it sorts the array into a descending order. ASSUMPTION: (1) Use three (almost) same-ranged buckets (2) Show (or explain) the steps as detail as possible. If needed, please illustrate the steps. A = [ 87 71 93 62 27 48 21 12 92 55 ](a) In this task we consider ptr as a 2D matrix. Whereas, number of rows would be fixed but make number of columns variables. To do this, instead of using arrays of fixed column size allocated on stack, you will make each element of array to have nColumns (passed as argument to the function) elements and store them on heap using new operator. Next, initialize the values of these arrays randomly using for loop and ptr. Finally display the sum of each individual array.You are not allowed to access the array using original variable name. (b) In the previous task we make number of columns of a 2D matrix variables. Here we will make number of rows variables as well. Thus we will have a way of defining a generic 2D matrix according to user choice. Now your goal is to write a function that receives three arguments: (i) an alias to a 2D pointer; (ii)number of rows; and (iii) number of columns; Now your goal is to first allocate the memory for rows and then for columns dynamically using new…
- (a) In this task we consider ptr as a 2D matrix. Whereas, number of rows would be fixed but make number of columns variables. To do this, instead of using arrays of fixed column size allocated on stack, you will make each element of array to have nColumns (passed as argument to the function) elements and store them on heap using new operator. Next, initialize the values of these arrays randomly using for loop and ptr. Finally display the sum of each individual array.You are not allowed to access the array using original variable name. (b) In the previous task we make number of columns of a 2D matrix variables. Here we will make number of rows variables as well. Thus we will have a way of defining a generic 2D matrix according to user choice. Now your goal is to write a function that receives three arguments: (i) an alias to a 2D pointer; (ii)number of rows; and (iii) number of columns; Now your goal is to first allocate the memory for rows and then for columns dynamically using new…python (input parsing) Program a method merge_sorted(a,b) that when given two sorted arrays a and b, returns a new sorted array c that has the elements from array a and array b. For example when givena = [1,3,5,6,10]b = [1,4,6,8] the resulting array should be: c = [1,1,3,4,5,6,6,8,10] This method should not call a sorting method. Instead, the resulting array should be produced by "zipping" the two input arrays together: we repeatedly select the least element that we did not consider before from a and b and include this in c. For example: a = [1,3,5,6,10] ^ b = [1,4,6,8] ^ c = [1,1,3,...] the arrows (^) point to the lowest element we did not consider before. Of these, element 4 from b is less than element 5 from a. For this reason, we select 4 as the next element and advance the arrow ^ for b to point to 6.Problem Description Inversion Count for an array indicates – how far (or close) the array is from being sorted. If array is alreadysorted then inversion count is 0. If array is sorted in reverse order that inversion count is the maximum.Formally speaking, two elements a[i] and a[j] form an inversion if a[i] > a[j] and i < j .Example: The sequence 2, 4, 1, 3, 5 has three inversions (2, 1), (4, 1), (4, 3).Requirement Design should be based on divide and conquer.Running time should NOT be worse than .Must use recursion to solve the subproblems. Input Specification Your program should read from an input file, which starts with a line indicating the number of test cases.Each of the following lines indicates a test case, and each test case includes a sequence of numbers(separated by spaces) for which you need to count inversions. Sample Input 32 4 1 3 51 2 4 8 9 3 5 6 1 20 6 4 5Output Specification For each test case, print one line with a format of The sequence has ? inversions in…
- 12) Fun With Mergesort. Given the recursive mergesort function below. Modify the msort function such that, msort calls msort for sub arrays with more than 1024 elements, and msort calls bsort for sub arrays with 1024 or less elements. Assume both functions operate on the same global array. int data[4294967296]; // REALLY BIG array void bsort (int f, int 1); // forward declaration void msort (int f, int 1) int m; if (f<1) { m - (f+1)/2; msort (f, m): msort (m+1,1): merge (f,m, 1);Please fill in the blanks where all the XXXXXXX is at .386 .model flat, stdcall .stack 4096 ExitProcess PROTO, dwExitCode: DWORD .data Array WORD 10, 2, 23, 45, 21, 11 MAXIMUM WORD ? .code main PROC mov ecx, LENGTHOF Array ; to loop through every item mov esi, OFFSET Array ; points to the first item of the array mov ax, 0 ; start with 0 as the highest value L1: XXXXXX ; compares current max with current item JAE L2 ; if ax is larger or equal to the current item, no change in ax. Just move to next element XXXXXXX ; update ax with the current element, so it becomes the new max L2: XXXXXXX ; move to the next item of the array loop L1 ; if there are more items, loop again mov MAXIMUM, ax ; finally, move the max value into MAXIMUM INVOKE ExitProcess, 0 main ENDP END mainComputer Science Selection sort Algorithm (Assembly language - masm in 32 bits) Write a program that sorts an array of a set of numbers in assembly language, masm in 32 bits. Sort the numbers in the array from ascending to descending and simply print the array. Remember the time complexity of the sorting algorithm is O(n^2) The array - {25, 62, 91, 15, 10, 11, 35, 78}