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- A pump lifts water at a rate of 283 liters per second from a lake and force it into a tank 8 m above the level of the water at a pressure of 137 kPa. what is the power required in kW?At sea level a nitrogen molecule has an average translational kinetic energy of 8.7 x 10-21 J. Its mass is 4.7 x 10-26 kg. If such a molecule could shoot straight up without striking other air molecules, how high would it rise? Express your answer in kmA circular swimming pool full of water has a diameter of 24 ft and the sides are 5 ft high. Set-up the integral for the work required to pump all of the water out over the side? ₂5 8985.6T (5-y)dy 12 1560π (12-y)dy 0 5 62.4π S (5-y)(y³-5y²-25y + 125)dy 5 748.8T S (5-y)dy
- Convert the following: 365 miph to m/s 98 rev/min to rad/s 4585 kJ/kg to BTU/lbConvert the following: 5698.4 in Hg to Mpa 25.95 Watts to in-lb/min 6469 kg/s to Hp 0.689 Hp to Erg/sArteriosclerotic plaques forming on the inner wall of arteries can decrease the effective cross-sectional area of an artery. Even small changes in the effective area of an artery can lead to very large changes in the blood pressure in the artery and possibly to the collapse of the blood vessel. Imagine a healthy artery, with blood flow velocity of vo equals 0.14 m/s and mass per volume of p = 1050 kg/m³. The kinetic energy per unit volume of blood is given pv². This is one of the terms in Bernoulli's equation. Imagine that plague has narrowed an artery to 1/10 of its normal cross-sectional area, a 90% blockage. 1 2 by ko = a) Compared to normal blood flow velocity, vo, what is the velocity of blood as it passes through this blockage? b) By what factor does the kinetic energy per unit of blood volume change as the blood passes through this blockage? c) Using Bernoulli's equation as the blood passes through this blockage, what happens to the blood pressure?
- Useful constants: k=9.00×109 N.m2/C2 ε0= 8.85×10-12 C2/N.m2 µ0=4π×10-7 T.m/A mp=1.67×10-27 kg me=9.11×10-31 kg e=1.6×10-19 C g=10.0 m/s2 --------- A toaster has a Nichrome (α=4.5×10-4 °C-1) heating element that has a resistance of Ro= 80 Ω at a temperature T=20 °C. When the toaster is turned on, the resistance of the element rises to 89.1 Ω and its temperature is increased. Find the final temperature (in oC) of the heating element.How far will 350 J raise a 7 Kg mass?Answer: W ≈ −1.182 x 10^6 J
- A pump can discharge about 137.6 liters of water in one day. This work done by the pump is equal to the work required to lift this amount of water a height equal to that of a 2-meter person. The density of water is 1 kg/L. What is the pump’s power in watts? The pump’s power is ___ watts.The work done in breaking a water drop of radius 1 cm into 64 equal droplets (surface tension of water is 0.07 N/m) (a) 1.6 × 10 ¹ J 4 (b) 264 × 10 ¹ J (c) 2.64 × 10 ¹ J (d) 5.28 × 10 ¹ JCalculate the work W in megajoules (1 MJ = 1 x 106 J) required to pump all of the liquid out of a half-filled, rectangular tank (see figure) through a hole in the top. Water exits here. a Assume that a = 4, b = 4, and c = 8. The density of water is 1000 kg/m³ and g = 9.8 m/s². (Use decimal notation. Give your answer to two decimal places.) +