Based from the Molarity (0.60) of the palmitic acid solution that you were able to solve from the previous problem, you are to prepare 250 mL of the said molar concentration. If you have an available 2M stock solution of Palmitic acid, How many mL of solvent do you need to add to the amount gotten from the 2M Palmitic acid stock solution to prepare 250 mL total volume of your desired solution?

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