Balanced Delta Connected Example R Vph = 240V VRY BN YN Y ZRY = ZYB = ZBR = 5+j2 For the balanced 3 phase Delta connected load determine the following:
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- Need asap pls help. Solve for the voltages across and currents through each component. Show the complete solution and explain. The total power should be zero..A parallel connection of a RL branch with a C branch is connected across a 100V AC mains. At first R = 10 ohms, L = 20mH and frequency of 1000rad / s, the current measured is 2.2361A at 89.44 leading power factor. A) Determine the initial capacitance. B) However, a fault occurs on the capacitor branch making its capacitance 20% lower and a resistance of 5 ohms is detected. If this faulty circuit is rerun but at a frequency of 500 rad / s, determine the new current that will flow through the circuit.Three load units A, B and C are connected in parallel and take currents that are respectively 12, 10 and 15 amperes. Assuming IA to be the reference phasor, IB leads IA by 30°, and IC lags IA by 65°, calculate the total current and the angle it makes with the reference.
- QUESTION 12 A single phase 600v/120v transformer has a load of 30 ohms resistive and 20 ohms inductive in series. what is the load power factor? O O O O O .91 O .39 .83 .42A 50 Hz, Scott connected transformer supplies an unbalanced two phase load at ( 400 V) per phase. For the leading phase the load has a resistance of (13.3 ohm) and capacitor of (318) micro farad in series. For the other phase the load consists of resistance (10) ohm and an inductance of (42.3) mH. Calculate both mathematically and graphically the lines currents on 3- phase side. The main transformer primary to secondary turns ratio is (12/1).what are the advantages and Disadvantages Connecting transformers 3 Phase between (delta to Star)
- A three-phase circuit is balanced. The source voltage for the a-phase has a magnitude of 100 volts, and you can assume the phase angle is a reference of 0 degrees. Write the phasor expressions with proper subscript notation for the source voltage for each leg of the three-phase source if it is in a positive phase sequence.Draw three transformers for each of the different three-phase connections. That is, draw three transformers and then make the connection, eg star-star, then redraw three transformers and make another three-phase connection, and so on until all four combinations of three-phase connections are made.From the circuit below, determine secondary winding voltage Vsec if the primary winding voltage Vpri = 120Vrms? Np:Ns 6:1 Vp 120 Vac 60 Hz out R = 200 ) O Ovrms O 720Vrms 120Vrms O 20Vrms wi m
- X₂=0.1 1 XL +03 Soto X₁ = 0.2 X = 0.1 X = 0.1 Above is the one-line diagram of a simple power system. Each generator is represented by an emf behind the subtransient reactance. All impedances are expressed in per unit on a common base. All resistances and shunt capacitance are neglected. The generators are operating on no load at their rated voltage with their emfs in phase. A symmetrical fault occurs at bus 1 through a fault impedance Z, =j0.08 per unit. a) Using Thevenin's Theorem, determine the impedance to the point of fault and the fault current in per unit. b) Find the bus voltages and line currents during the fault. 2 O oto6.5% ans ex A so kvA. 2o00/20 V, So He single-phase transformar has impedance drof of8% and resistance drop of 4%. Caleulate. The Requlation of the Thams former at full- Load o8 P.s Legging. also find The Power factor at which Voltage requlation will Be Zero. Sols 0.5 leading. s alculate The % Noltege Requlation af atransformar in w hich the Percantage resistance drof is 1% and Percentage dre is 6% when The Power fador is 0.8 lagging ) > unity aMS 38 % ans 1 % (シ→ 0.8 leading . amS - 2.2%In no load Phasor diagram of practical transformer, the core loss current Ic is with primary voltage Vp. In phase O 90 degrees Leading 90 degrees Lagging O All the above