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- Design a 6-bit ripple carry adder. Experimentally find out the sum of 110011 and 111001. Construct your entire schematic diagram and label all necessary pins and simulate for results.DISCUSSION: 1- Design the logic eircuit for the following conditions and draw the output wave form, X is a 0 if any two of the three variables A, B, and C are 1, X is al for all other conditions. 2- Implement the following function with only AND and NOT gates, F-AB+AB+BC W-XY (XZ+XY Z+ Y Z) + XZ 3- Use NAND gate, NOR gate, or combinations of both to implement the following expression:- a) X-A [B + C (D +E)] b) X B (CDE+EF G) (A B+ C) 4-a) What is the applications of AND gate and OR gate? b) In OR gate why 1 +1 1? c) The Fig. (1-12 ) shows the A & B inputs and the output is C, For the OR gate using the A and B inputs of Fig. (1-12) draw the C output for each of the following: The AND gate. • The NAND gate. • The NOR gate. .The EX-OR gate. • The EX-NOR gate. 1-12After the execution of the following program, the content of PORTB is: PORTB EQU OF81H MOVLW OFFH MOVWF PORTB BCF PORTB, O Select one: a. OFFH b. 11111110 binary c. 01111111 binary d. 11111101 binary
- parity generator design, construct and test a circuit that generates an even parity bit ffrom four messages bits . use XOR gates. adding one more XOR gate, expand the circuit so that it generates an odd parity bit also.The input to a combinational logic circuit is 4-bit binary number (A, B, C, D). Design the circuit strictly using NAND gate with two outputs (Y1 and Y2) for the following conditions: Output Y1 is low when the input binary number is less than or equal to 7. Output Y2 is high when the input binary number is less than or equal to 7.Instructions A designer at Channel Microsystem needs to design basic logic gates with the use of PN junction diodes, light emitting diodes (LED), 5-V power supply and resistors. The logic gates are to be tested through random input logic pulse and verified in time domain analysis. A O A O Out Out BO BO OR NOR A O Out Out BO в о AND NAND Figure 1 HIGH '1' DIODE-DIODE LOW '0' LOGIC Out GATES во Figure 2 Figure 1 illustrates the combination of logic gates to be developed using diode-diode logic. Figure 2 describes the simulation testbench setup in verifying the operation of the logic gates developed through diode-diode logic. Design and verify the diode-diode logic with low
- An equation in reduced SOP form, is F=AB+B'C+A'C'. I need to draw a logic circuit F using NOT/AND/OR and logoc circuit F using all NAND gates. Thank you for the help. I understood the previous types of gates but I am confused on how to draw these circuits.Design counter that counts from 00 to 59, using the IC 74LS90 ripple counter and use two 7 segment display to display the result count. You can also use 7447 binary to 7-segment Display Decoder shown below.B) Draw the logic circuit for each of the following: 3) The expression (XY + Z + XYZ + X) by using NAND gate or
- VII) Convert from (i) (ii) Find the binary equivalent of the BCD number (0100 1001 1001.0100 0011 0011)BCD Find the BCD equivalent of the binary number 110100010.101102T: Answer thne f. questions: 1) The hexadecimal number ´Al' has the decimal value equivalent to (A) 80 (B) 161 (C) 100 (D) 101 2) The output of a logic gate is 0 when all its inputs are logic 1. The logic is either (A) a NAND or an EX-OR (B) an OR or an EX-NOR (C) an AND or an EX-OR (D) an NOR or an EX-NOR 3) The Gray code of the Binary number 1100111 is (A) 1011011 (B) 1010100 (C) 1001001 (D) 101101 4) When simplified with Boollean Algebra (a+b)(a+c) simplifies to (A) a (B) a+a(b+c) (C) a(1+bc) (D) a+bc 5) -31 is represented as a sign Binary number ( using Sign-magnitude form ) equal to (A) 00011111 (B) 10101001 (C) 01110010 (D) 00101101 6) The Binary number 110111 is equivalent to decimal number (A) 25 (B) 55 (C) 26 (D) 34 7) With 4 bit, what the range of decimal values if the number is 2's complement signed number. (A) -32 to +31 (B) -2 to +1 (C) -8 to +7 (D) None of theseMatch the following binary code (A) into BCD representation (B): 0100 0001 0111 0110 A. 0111 B. 0110 C. 0100 D. 0001