Answered: B) A constant force F= (4 N) i + (2 N)…

B) A constant force F= (4 N) i + (2 N) j-(4 N) k acts on a particle which makes displacement of 5 m in the +Z-direction, calculate the work done by this force on the practical?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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F1 = 500 N A) 1200 k Nm 4 m O B) 1200 j +1200 k Nm F3 C) 1200 i Nm 3 m y D) 1200 i- 1200 j Nm 2 m F2 = 400 N %3D E) 1200 j Nm F3 = {-200i + 500j – 300k} N. Express the moment of F, about point O.
äbäi 15 Q2) The Resultant force of forces A and B shown in fig. is 39 15N C) R=19.02N O A) R= 75.01N B) R= 99.01 N D) R= 91.7N 火立

1-A particle is moving with an initial velocity of v, = 24 of when a = -15v³, what its positive velocity component at t = 10 s? when t = 0. If it is subjected to a deceleration %3D a) 0.022 m/s b) 0.007 m/s c) 0.096 m/s d) 0.058 m/s e) 0.011 m/s f) None of them
719 @ • ৭:৭, 3G ZAIN IQ li. خاص A docs.google.com Untitled Section F1 = 5 kN F2 = 13 kN )- 60° F3 = 4 kN 6-45 4 m 8 m F4 = 22 kN D El Ja = 30° F5 = 4 kN 1] What is the resultant moment of the five forces acting on the rod about point A? a) 3.5 kN.m b) 16.2 kN.m c) 20.2 kN.m d) 11.5 kN.m e) 33.1 kN.m f) S.1 kN.m 21 What is the resultant moment of the five forces acting on the rod about point C? a) 47.5 kN.m b) 55.5 kN.m c) 12.2 kN.m d) 61.9 kN.m e) 79.1 kN.m ) 44.1 kN.m 3] What is the moment of the force F1 about point E? а)- 22.8 kN.m b) - 49.5 kN.m c) - 55.9 kN.m d) - 9.1 kN.m e) - 12.7 kN.m f) - 25.9 kN.m 4] What is the moment of the force F2 about point D? a) 40.5 kN.m b) 71.5 kN.m c) 14.2 kN.m d) 64.5 kN.m e) 56.1 kN,m ) 39.1 kN.m 5] What is the moment of the force F5 about point A? a) – 17.8 kN.m b) - 4.8 kN.m c) - 12.9 kN.m d) - 8.1 kN.m e) - 32.7 kN.m f) - 2.9 kN.m ;The answer is [1 * a
F4 Consider the following values: - FS a- 25 m; b- 5 m: e- 25 m; d = 5 m; F1 = 5 EN; 12 = 6 kN; F3 = 7 kN; 4 = 8 kN; P5 = 9 kN; a= 30°, 0- 60° - 30° 1] What is the resultant moment of the five forces acting on the rod about point A? )- 784 KN.m b) 82.7 KN.m 9-546 KN.m d) 92.9 KN.m e) 24.1 KN.m 0-47.1 KN.m 21 What is the resultant moment of the five forces acting on the rod about point B? b) - 201.6 KN.m d) - 128.9 KN.m ) 215.4 KN.m D- 144.2 kN.m a) SSKN.m ) 131.6 KN.m 31 What is the resultant moment of the five forces acting on the rod about point C? a) - 186.7 KN.m b) 21I KN.m 0)-209.1 KN.m d) 127.9 KN.m e)-174.1 KN.m ) 35.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? d) - 200.7 AN.m ) 27.1 AN.m 9- 300.1 kN.m a)- 217SKN.m b) s2.7AN.m ) 1219AN.m
10. In the figure below, h, = 1.20 m, h, = 0.80 m, and the length along the wire from A to C is 6.00 m. A 3.00-gram bead starting from rest at A slides along the wire to point C and stops. How large an average friction force opposed its motion? h2 B A) 1.45 x 103 N B) 3.12 x 10 N C) 2.55 x 103 N D) 1.96 x 10³ N
F3 = 800 N O A) 400 i -600 jN + 800 k Newton O B) 600 i-800j Newton F2 = 500 N %3D 370 C) 600 i+400j Newton D) 800 i+ 600j Newton y F1 = 1000 N F, is on the x-y plane. 1 E) 400 j+ 600 k Newton The angle between F3 and x axis is 135° , between F3 and y axis is 60°. Express force F, in vector form.
For figure (2): The arm in is subjected to five forces as follows: F1 = 135 N, F2 = 98 N, F3 = 210 N, F4 = 56 N. If the y - direction resultant force is 144 N, and ox = 40°, 0 = 50°, B = 70°: 3 - What is the magnitude of the force Fs? a) 318.4 N b) 99.IN c) 151.6 N d) 36.5 N e) 111.2 N ) 18.8 N g) None of them 4 - What is the magnitude of the resultant of these five forces? a) 269.4 N b) 157.1N c) 354.5 N d) 280.6 N e) 155.4 N f) 329.1 N g) None of them 5 - What is the direction of resultant measured counterclockwise from the positive x-axis? a) 13.6° b) 285.5° c) 30.8° d) 110.1° e) 72.3° f) 190.9° g) None of them
F1-5 kN F2 - 13 kN 0-45 F3=4 kN B. 4m F4 22 kN E 30 FS = 4 kN 1] What is the resultant moment of the five forces acting on the rod about point B? ) 39.1 KN.m d) 18.5 KN.m e)9.1 EN.m D 21.1 KN.m a) 40.5 kN.m b) 49.5 kN.m 2] What is the resultant moment of the five forces acting on the rod about point E? a) - 22.8 kN.m b) - 28 KN.m e)- 18.9 AN.m d) - S.1 EN.m e)- 12.7 AN.m 9-7.5 kN.m 31 What is the moment of the force F1 about point D? a) - 27.8 KN.m b) - 128 EN.m - 38.9 kN. d) - 19.1 KN.m e) - 32.7 kN.m 9- 29.2 kN.m 41 What is the moment of the force F2 about point E? a) 77.5 KN.m b) 55.5 KN.m )142 Nm d) 32.5 EN.m e) 7.1 KN.m ) 84.1 KN.m Activate Windows Go to Settings to activate Win e) - 29.7 kN.m 5] What is the moment of the force F5 about point B? a) - 39.8 kN.m b) - 18.8 kN.m c) - 12.8 KN.m d) - 4.1 kN.m f)- 25.9 KN.m WE
17. A particle is moving along the curve y=2x+e* such that its abscissa is increasing at the rate of 2 cm/s. How fast is the y coordinate changing at the instant that its abscissa is 3 cm? A) 44.17 cm/s B) 53.19 cm/s C) 62.76 cm/s D) 25.87 cm/s
In figure (2), the friction coefficient between the crate and truck top surface is (0.5). If the truck initially moves at a speed of 50 km/hr. Figure (2) 3) What is the minimum stopping distance that the truck can have with constant acceleration? a) 8.2 m b) 64.2 m c) 35.3 m d) 22.5 m e) 54.9 m f) 19.7 m 8) None of them
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