Java program to return the third smallest element in the Binary Search Tree in O(n) time.VERY IMPORTANT: The value of the third smallest element is ”3”. You may choose either a recursive or an iterative solution, but you are NOT allowed to maintain an extra array to store values of the tree elements for a linear scan later to return the required value. Also, you can’t just return 3 :) (4) Consider the Binary Search Tree(BST) provided below:1/* Class to represent Tree node */class Node {int data;Node left, right;23456.public Node (int item)8data = item;310left = null;right = null;111213 }1tree.root = new Node (4);tree.root.left = nev Node (2);tree.root.right = new Node (6);tree.root.left.left = new Node (1);6 tree.root.left.right = new Node (3);tree.root.right.left = new Node (5);tree.root.right.right = nev Node (7);348.

Solution: Given, Node Structure is- class Node { int data; Node left, right; Node(int item) {…

Answered: ava program to return the third…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

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Java program to return the third smallest element in the Binary Search Tree in O(n) time.

VERY IMPORTANT: The value of the third smallest element is ”3”. You may choose either a recursive or an iterative solution, but you are NOT allowed to maintain an extra array to store values of the tree elements for a linear scan later to return the required value. Also, you can’t just return 3 :)

(4) Consider the Binary Search Tree(BST) provided below:
1
/* Class to represent Tree node */
class Node {
int data;
Node left, right;
2
3
4
5
6.
public Node (int item)
8
data = item;
3
10
left = null;
right = null;
11
12
13 }
1
tree.root = new Node (4);
tree.root.left = nev Node (2);
tree.root.right = new Node (6);
tree.root.left.left = new Node (1);
6 tree.root.left.right = new Node (3);
tree.root.right.left = new Node (5);
tree.root.right.right = nev Node (7);
3
4
8.

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