At the national spitting competition, contestants were lined up on top of a tall building. The winning projectile was projected off the top of the building in a trajectory defined by the following equation where the height (h) is in metres above the ground and time (t) is in seconds since the projectile was launched. h=-4.9t^2+29.4t+37.9 Show all work when answering the following (no guess and check allowed): a) If the mouth of the person who launched the winning projectile was 1.6 metres above the roof of the building, how tall was the building? b) To the nearest tenth of a second, how long was the projectile in the air before it hit the ground? (Nearest tenth of a second = one decimal place) c) To the nearest tenth of a second, determine how long the projectile was at or above 80m in height.
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At the national spitting competition, contestants were lined up on top of a tall building. The winning projectile was projected off the top of the building in a trajectory defined by the following equation where the height (h) is in metres above the ground and time (t) is in seconds since the projectile was launched.
h=-4.9t^2+29.4t+37.9
Show all work when answering the following (no guess and check allowed):
a) If the mouth of the person who launched the winning projectile was 1.6 metres above the roof of the building, how tall was the building?
b) To the nearest tenth of a second, how long was the projectile in the air before it hit the ground? (Nearest tenth of a second = one decimal place)
c) To the nearest tenth of a second, determine how long the projectile was at or above 80m in height.
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