Approximating displacement The velocity in ft/s of an object moving along a line is given by v = 3t² + 1 on the interval 0 ≤ t ≤ 4, where t is measured in seconds. Q a. Divide the interval [0, 4] into n = = 4 subintervals, [0, 1], [1, 2], [2, 3], and [3, 4]. On each subinterval, assume the object moves at a constant velocity equal to v evaluated at the midpoint of the subinterval, and use these approximations to estimate the displacement of the object on [0, 4] (see part (a) of the figure). b. Repeat part (a) for n = 8 subintervals (see part (b) of the figure). 50- 40+ 30- 20+ 10- 0 1 2 v = 31² + 1 (a) 3 4 t 50 40+ 30 20+ 10+ 0 1 2 (b) v = 31² + 1 I 3 4 t

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
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Chapter4: Polynomial And Rational Functions
Section4.6: Variation
Problem 11E
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answers (a) =67ft and (b) = 67.75ft 

15. Approximating displacement The velocity in ft/s of an object moving
along a line is given by v = 3t² + 1 on the interval 0 ≤ t ≤ 4, where t is
measured in seconds.
a. Divide the interval [0, 4] into n = 4 subintervals, [0, 1], [1, 2], [2, 3],
and [3,4]. On each subinterval, assume the object moves at a
constant velocity equal to v evaluated at the midpoint of the
subinterval, and use these approximations to estimate the
displacement of the object on [0, 4] (see part (a) of the figure).
b. Repeat part (a) for n = 8 subintervals (see part (b) of the figure).
v = 31² + 1
50
40
30
1ZZ
20
10-
0
50
40
30
20-
10
0
2
(a)
3
2
(b)
= 31² + 1
3
Transcribed Image Text:15. Approximating displacement The velocity in ft/s of an object moving along a line is given by v = 3t² + 1 on the interval 0 ≤ t ≤ 4, where t is measured in seconds. a. Divide the interval [0, 4] into n = 4 subintervals, [0, 1], [1, 2], [2, 3], and [3,4]. On each subinterval, assume the object moves at a constant velocity equal to v evaluated at the midpoint of the subinterval, and use these approximations to estimate the displacement of the object on [0, 4] (see part (a) of the figure). b. Repeat part (a) for n = 8 subintervals (see part (b) of the figure). v = 31² + 1 50 40 30 1ZZ 20 10- 0 50 40 30 20- 10 0 2 (a) 3 2 (b) = 31² + 1 3
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