Answer: Pmax i kN
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- Current Attempt in Progress The rectangular bar is connected to the support bracket with a 11-mm-diameter pin. The bar width is w-70 mm and the bar thickness is 10 mm. Each side of the bracket has the same dimensions as the bar. The average shear stress in the pin cannot ex t exceed 100 MPa, the bearing stress in the bar cannot exceed 150 MPa, and the bearing stress in the bracket cannot exceed 140 MPa. Determine the maximum value of Pax that can be supported by the structure. Answer: Pax 3 KNThe rectangular bar is connected to the support bracket with a 27-mm-diameter pin. The bar width is w = 65 mm and the bar thickness is 10 mm. Each side of the bracket has the same dimensions as the bar. The average shear stress in the pin cannot exceed 125 MPa, the bearing stress in the bar cannot exceed 120 MPa, and the bearing stress in the bracket cannot exceed 130 MPa. Determine the maximum value of Pmax that can be supported by the structure. Answer: Pmax= P Mi KNThe rectangular bar is connected to the support bracket with a 26-mm-diameter pin. The bar width is w=60 mm and the bar thickness is 15 mm. Each side of the bracket has the same dimensions as the bar. The average shear stress in the pin cannot exceed 120 MPa, the bearing stress in the bar cannot exceed 120 MPa, and the bearing stress in the bracket cannot exceed 120 MPa. Determine the maximum value of Pmax that can be supported by the structure. Answer: Pmax KN
- The rectangular bar is connected to the support bracket with a 17-mm-diameter pin. The bar width is w = 80 mm and the bar thickness is 15 mm. Each side of the bracket has the same dimensions as the bar. The average shear stress in the pin cannot exceed 125 MPa, the bearing stress in the bar cannot exceed 150 MPa, and the bearing stress in the bracket cannot exceed 150 MPa. Determine the maximum value of Pmax that can be supported by the structure. P KN Answer: Pmax= iThe rectangular bar is connected to the support bracket with a 17-mm-diameter pin. The bar width is w = 70 mm and the bar thickness is 15 mm. Each side of the bracket has the same dimensions as the bar. The average shear stress in the pin cannot exceed 115 MPa, the bearing stress in the bar cannot exceed 140 MPa, and the bearing stress in the bracket cannot exceed 150 MPa. Determine the maximum value of Pmax that can be supported by the structure.Two loads P act as shown, one parallel to (x0) and another parallel to z0; each load P equals 2.5 kN. The crankshaft dimensions are b1 = 80 mm, b2 = 135 mm, and b3 = 55 mm. The diameter of the upper shaft is d = 26 mm. Determine the normal stress at point B, which is located on the surface of the upper shaft at the yo axis. Yo Хо b3 Lütfen birini seçin: a. 149.606 MPa b. 324.676 MPa c. 139.544 MPa d. None e. 190.884 MPa
- Two loads P act as shown, one parallel to (x0) and another parallel to z0; each load P equals 1.5 kN. The crankshaft dimensions are b1 = 55 mm, b2 = 150 mm, and b3 = 45 mm. The diameter of the upper shaft is d = 22 mm. Determine the normal stress at point A, which is located on the surface of the upper shaft at the z0 axis. | Yo by bz Lütfen birini seçin: a. -302.704 MPa b. -155.971 MPa c. None d. -200.302 MPa e. -147.437 MPa2. If the allowable shear stress for each of the steel pins at A and B is tpe 6.5 ksi and the allowable normal stress for bar CB is Operm 10 ksi, determine the diameter of the pins at A and B and that of the square bar CB. Pin A is in double shear while Pin B is in single shear. Ignore points D and E. (^ } 2.5 ft -3 ft -5 ft 150 lb/ft Fx =The cylindrical steel column has an outer diameter of 4 in. and inner diameter of 3.5 in. The column is separated from the concrete foundation by a square bearing plate. The working compressive stress is 26 000 psi for the column, and the working bearing stress is 1200 psi for concrete. Find the largest force P that can be applied to the column. Express your answer in Ib. 4 in. 3.5 in. 4/4 7 in.
- 2. The bar AC is supported by a pin at A and a cable that runs from B to E around the frictionless pully at D. If the allowable tensile stress oallow = 5.2 ksi for the cable, determine the required minimum diameter (inch) of the cable. The cylinder (connected at C) weighs 890 lb. Neglect weight and thickness of the bar AC. D 4 3 A C 5 ft 5 ft -4 ft 890 lbLink AB, of width b = 2 in. and thickness t = 1414 in., is used to support the end of a horizontal beam. The average normal stress in the link is -18 ksi and the average shearing stress in each of the two pins is 12 ksi. Determine the average bearing stress (ksi). **The way I had solved it was that I used the given normal stress to first find the P force needed to plus into my bearing stress formula. I still however need the diameter. The answer key says to use the given shear stress equation to find the diamter, how do you know to use that and not the shear stress formula again?The collar bearing shown is subject to a 500 kN force. 500 kN The collar is 25 mm thick. Find d and D (to the nearest mm) so that the allowable normal stress in the column collar bearing of o = 280 MPa, the allowable shear stress in the collar collar of t = 200 MPa and the allowable bearing stress between the collar and the support of ob = 70 MPa is not exceeded.