Answer H92L We (A) Al₂O3 + 3H₂SO4 8kg-mol Al₂O3 and mal IMAho react with Mol 1₂2504 8x3 = 24 kg-mol thSony we required only 24kg and limiting excess reactant is Hysoy reactant Abo That means above disscasion 8kg-mole react with 24 kg-mol H₂SO4 We have 40 kg- mole mole of excess percentage = of theor H₂SO4 8 kg-mol Al₂o reacting with have 40 kg-mol H₂₂ Sou that means will be excess percentage I th Sou → Al₁₂ (S0₂₁)3 + 3 tho 40kg-mol th 50₂ react in 3 mol In sou will be 8kg-mol = 8000 mol mass of AL₂O3 Mass of 8 kg md Al2(104)3= - reaction efficiency = freaction efficiemy T = while = 4014-mal excess mol of the say Total Mol of the son 40% So remain mole or excess 24 kg-mol mixture 1 *100 819-mol A/₂ 0₂ Convert completely. so we know that Abo, is limiting reactant and limiting reactant és completely convest in to product at the end of the reaction, that means 16 Ку-т-1 yoly-md 814 Conversion pescentige of Ako -XIOD 100% 818. (c) 8-kymol Aboz produce = 8 19- and Alat Sou) by storchrometry of the reaction because 1-mole Abo produce 8 ty-mol A₂₂0₂ produced mole x moleculas mass = goromol x 1029/² govo mol x 342% / mal Mass of Ah₂2 03 (Input) les Mass of Ab(Son) (auto)ing 298257 x100= = = 16kg-und नाळ Imol Al2(SO4)3 8 lg-mol Ah (Sur) } 816 ку 2736 к Al Свси) з 81619 ³x100 27365
Answer H92L We (A) Al₂O3 + 3H₂SO4 8kg-mol Al₂O3 and mal IMAho react with Mol 1₂2504 8x3 = 24 kg-mol thSony we required only 24kg and limiting excess reactant is Hysoy reactant Abo That means above disscasion 8kg-mole react with 24 kg-mol H₂SO4 We have 40 kg- mole mole of excess percentage = of theor H₂SO4 8 kg-mol Al₂o reacting with have 40 kg-mol H₂₂ Sou that means will be excess percentage I th Sou → Al₁₂ (S0₂₁)3 + 3 tho 40kg-mol th 50₂ react in 3 mol In sou will be 8kg-mol = 8000 mol mass of AL₂O3 Mass of 8 kg md Al2(104)3= - reaction efficiency = freaction efficiemy T = while = 4014-mal excess mol of the say Total Mol of the son 40% So remain mole or excess 24 kg-mol mixture 1 *100 819-mol A/₂ 0₂ Convert completely. so we know that Abo, is limiting reactant and limiting reactant és completely convest in to product at the end of the reaction, that means 16 Ку-т-1 yoly-md 814 Conversion pescentige of Ako -XIOD 100% 818. (c) 8-kymol Aboz produce = 8 19- and Alat Sou) by storchrometry of the reaction because 1-mole Abo produce 8 ty-mol A₂₂0₂ produced mole x moleculas mass = goromol x 1029/² govo mol x 342% / mal Mass of Ah₂2 03 (Input) les Mass of Ab(Son) (auto)ing 298257 x100= = = 16kg-und नाळ Imol Al2(SO4)3 8 lg-mol Ah (Sur) } 816 ку 2736 к Al Свси) з 81619 ³x100 27365
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Answer
H922
We
(A)
Al₂O3 + 3H₂SO4
8kg-mol Al₂O3 and
mal
IMAho react with
Mol
1₂2504
8x3
= 24 kg-mol throu
we required only 24kg
excess reactant is Hesoy
and limiting
reactant
Abo
That means above disscasion 8kg-mole react with
24 kg-mol H₂SO
We
have
mole of
-
excess percentage =
of theor
Hasou
8 kg-mol Al₂o reacting with
have
40 kg-mol H₂₂ Sou
that means
will be
excess percentage
I th Sou
→
Al₁₂ (S0₂₁)3 + 3 tho
40kg-mol th 50₂ react in
3 mol
In sou will be
-
40 kg- mole
= 8000 mol
8kg-mol
mass of AL₂O3
Mass of 8 kg md Al2(104)3=
reaction efficiency =
freaction efficiemy
T
while
=
=
4014-mal
excess mol of the soy
Total Mol of the son
40%
So remain mole or excess
24 kg-mol
16 Ку-т-1
yoly-md
819-mol A/₂ 0₂ Convert completely. so
mixture
-*too
we know that
Abo, is limiting reactant and limiting
reactant és completely convest in to product at the
end
of
the
reaction,
that means
814
Conversion pescantige of Aloz
-XIOD
100%
81g.
(c) 8-kymol Aboz produce = 8 19- and Ala (sou) by storchrometry
of the reaction because
1-mole Abo produce
8y-mol A₂₂03 produced
mole x moleculas mass = goromo1 x 1029/²
govo mol x 342% / mal
mass of Ah₂2 03 (Input) les
Mass of Ab(Son) (autoffing
298257
x100=
=
=
16kg-und
Xtoo
Imol Al2(SO4)3
8 lg-mol Ak₂ (Sun) }
816 ку
2736 к Al Свси) з
81619
"X1000
27365
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