Answer all 3 Que:1 Solve the following: a) Mercury has a Semi-major axis length of 5.790905 X 1010 m and a semi-minor axis length of 5.667152 X 1010 m. Calculate Mercury's eccentricity to four significant digits. b) The orbit of Europa around Jupiter has a2= 4.5011 X 1011 and b2= 4.5007 X 1011. Find the eccentricity of Europa to three decimal places. c)When Earth is at aphelion, it is 1.52100 X 108 km from the sun. When it is at perihelion; the earth is 1.47095 X 108 km from the sun. Find the eccentricity of the earth's orbit to three decimal places.

Answer all 3 Que:1 Solve the following: a) Mercury has a Semi-major axis length of 5.790905 X 1010 m and a semi-minor axis length of 5.667152 X 1010 m. Calculate Mercury's eccentricity to four significant digits. b) The orbit of Europa around Jupiter has a2= 4.5011 X 1011 and b2= 4.5007 X 1011. Find the eccentricity of Europa to three decimal places. c)When Earth is at aphelion, it is 1.52100 X 108 km from the sun. When it is at perihelion; the earth is 1.47095 X 108 km from the sun. Find the eccentricity of the earth's orbit to three decimal places.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter11: Gravity, Planetary Orbits, And The Hydrogen Atom

Section: Chapter Questions

Problem 21P: Comet Halley (Fig. P11.21) approaches the Sun to within 0.570 AU, and its orbital period is 75.6 yr....

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Answer all 3 Que:1 Solve the following: a) Mercury has Semi major axis length of 5.790905 X 1010 m and semi-minor axis length of 5.667152 X 1010 m. Calculate Mercury's eccentricity to four significant digits. b) The orbit of Europa around Jupiter have a2= 4.5011 X 1011 and b2= 4.5007 X 1011.Find the eccentricity of Europa to three decimal places. c)When earth is at aphelion, it is 1.52100 X 108 km from the sun. When it is at perihelion; the earth is 1.47095 X 108 km from the sun. Find the eccentricity of earth's orbit to three decimal places.
The planet Mars is orbited by two small moons, Phobos and Deimos. Both moons have circular orbits. Use Kepler's Third Law in Newtonian form to compute both the product GM(Mars), where G is Newton's constant and M(Mars) is the mass of Mars, and the mass of Mars itself from the orbital data for the two moons and Newton's constant. 2. a) Phobos: P = 0.3189 days, a = 9377 km. b) Deimos: P = 1.2624 days, a = 23,460 km. %3D NOTE - The orbital periods are in earth days; 1 day = 24 hours = 86,400 s. %3D %3D Newton's constant is G = 6.673 x 10^(-11) m^3/kg s^2.
Neptune orbits the Sun with an orbital radius of 4.495 x 10^12 m. If the earth to sun distance 1A.U. = 1.5 x 10^11 m, a) Determine how many A.U.'s is Neptune's orbital radius (Round to the nearest tenth). b) Given the Sun's mass is 1.99 x10^30 kg, use Newton's modified version of Kepler's formula T^2 = (4pi^2/Gm(star)) x d^3 to find the period in seconds using scientific notation. (Round to the nearest thousandth). C) Convert the period in part b) to years (Round to the nearest tenth)
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A) When one object is orbiting a much larger object, the period of the orbit (T) is related to the semi‐major axis (r) by the general form of Kepler’s 3rd Law. Write this general form in the space below: B) What units must the period be in if we want to calculate the semi-major radius in meters? Note that G = 6.67 x 10-11 N m2/kg2. Complete problems using Kepler’s 3rd law as you wrote it down above:
The orbit of mars about the sun is elliptical with the sun at one focus. If the minor axis of this orbit is 2.25?10^8 kilometers and the eccentricity is about 0.093, determine the greatest distance of mars from the sun. a. 1.13?108?? b. 1.23?108?? c. 1.33?108?? d. 1.43?108??
GPS (Global Positioning System) satellites orbit at an altitude of 2.7x10^7m. You may want to review (Pages 392-398) Part A Find the orbital period Express your answer using two significant figures. 19 ΑΣφ ? T- h Submit Part B Find the orbital speed of such a satelite. Express your answer using two significant figures. 150 AC ? Submit Request Answer
a) Observations and trigonometry can be used to determine that Earth's moon has an orbital period of 27.32 days and a mean orbital radius of 384,400 km. Using this information, calculate the mass of the Earth. 2 M = 47² ² 2 C M= 4+1 (30214100000) 667 e
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4 Hello, I have questions about the physics, can you please help me with your diagram and explanation? I am highly appreciate it and thank you very much! In 1843, a comet passed extremely close to the sun, mass Ms: its distance from the perihelion was d = 6.1*10^3 * a0, where a0 is the radius of the Earth's orbit. Accurate measurements showed that the eccentricity of the comet was e=1-x with x = 9.4*10^-5. Given u = 30 km/s is the speed of revolution of the Earth around the Sun. (a) Express the product GMs as a function of u and a0. (b) Considering that the trajectory of the comet is quasi-parabolic, calculate its speed of passage vp at the perihelion. (c) Deduce the speed Va of transition to aphelion as a function of Vp and x. Do the digital application. (d) In what year will this comet return to the solar system?