Another way to find the first address, the last address, and the number of addresses is to represent the mask as a 32-bit binary (or 8-digit hexadecimal) number. This is particularly useful when we are writing a program to find these pieces of information. In Example 19.5 the /28 can be sented as 11111111 11111111 11 repre- 11110000 (twenty-eight 1s and four Os). Find a. The first address b. The last address c. The number of addresses

Another way to find the first address, the last address, and the number of addresses is to represent the mask as a 32-bit binary (or 8-digit hexadecimal) number. This is particularly useful when we are writing a program to find these pieces of information. In Example 19.5 the /28 can be sented as 11111111 11111111 11 repre- 11110000 (twenty-eight 1s and four Os). Find a. The first address b. The last address c. The number of addresses

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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A number in base 2 (binary) is a number such that each of its digits is 0 or 1. To convert frombinary to decimal (base 10), the digits starting from the right are multiplied by powers of 2(starting at 0) and added. For example, the value in decimal of 10011 is calculated as follows:
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Write a MIPS program that asks the user to enter an unsigned number and read it. Then swap the bits at odd positions with those at even positions and display the resulting number. For example, if the user enters the number 9, which has binary representation of 1001, then bit 0 is swapped with bit 1, and bit 2 is swapped with bit 3, resulting in the binary number 0110. Thus, the program should display 6. ***Please only the answer is MIPS assembly code not other language!
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