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- A horizontal force, F1 = 55 N, and a force, F2 = 17 N acting at an angle of 0 to the horizontal, are applied to a block of mass m = 3.9 kg. The coefficient of kinetic friction between the block and the surface is uk 0.2. The block is moving to the right. = Randomized Variables F₁ = 55 N F₂=17 N m = 3.9 kg o vi ble. on d ed ed FN=46.72 (b) Solve numerically for the magnitude of acceleration of the block, a in m/s², if 0 = 30°. (a) Solve numerically for the magnitude of the normal force, FN in Newtons, that acts on the block if 0 = 30°. ✓ Correct! a = 15.487 tan() П acos() E 14 sinh() 1 * 1 tanh() cotanh() Degrees O Radians 2 0 VO BACKSPACE sin() cos() cotan() asin() atan() acotan() cosh() Submit Hint . Feedback 7 85 9 6 3 I give up! • DEL HOME ← END y. CLEAR X Hk m 0The figure shows Superhero and Trusty Sidekick hanging motionless from a rope. Superhero’s mass is 82 kg, while Trusty Sidekick’s is 65 kg, and the mass of the rope is negligible. Randomized Variables m1 = 82 kgm2 = 65 kg a) Find the tension in the rope above Superhero in Newtons. b)Find the tension in the rope between Superhero and Trusty Sidekick in Newtons.Consider the 63 kg ice skater being pushed by two others shown in the figure. The coefficient of static friction is μs=0.4 and kinetic is μk=0.02.Randomized Variablesm = 63 kgF1 = 238 NF2 = 175 N Find the magnitude of Ftot, the total force exerted on her by the others, given that the magnitudes F1 and F2 are 238 N and 175 N, respectively in Newtons. Find the direction of Ftot (in degrees relative to the horizontal), the total force exerted on her by the others, given that the magnitudes F1 and F2 are 238 N and 175 N, respectively .What is the maximum value of the static friction force, in Newtons, that can act on the skater before she moves? What is her acceleration assuming she is already moving in the direction of Ftot in m/s2?
- 9. Consider the falling object of mass 10 kg in Example 2, but assume now that the drag force is proportional to the square of the velocity. a. If the limiting velocity is 49 m/s (the same as in Example 2), show that the equation of motion can be written as 1 (49² - 1²). 245 dy dt Also see Problem 21 of Section 1.1. b. If y(0) = 0, find an expression for v(t) at any time. Gc. Plot your solution from part b and the solution (26) from Example 2 on the same axes. d. Based on your plots in part c, compare the effect of a quadratic drag force with that of a linear drag force. e. Find the distance x(t) that the object falls in time t. Nf. Find the time T it takes the object to fall 300 m.A 1060 kg artillery shell is fired from a battleship. While it is in the barrel of the gun, it experienced an acceleration of 2.1x10^4 m/s^2. Randomized Variables M=1060kg A=2.1x10^2 m/s^2 (A) what net force is exerted on the artillery shell before it leaves the barrel of the gun (in Newton’s)? (B) what is the magnitude of the force exerted on the ship by the artillery shell in Newton’s?A chandelier hangs h = 0.62 m down from two chains of equal length. The chains are separated from one another by a length L = 0.45 m at the ceiling. The chandelier has a mass of m = 21 kg.Randomized Variablesh = 0.62 mL = 0.45 mm = 21 kgWhat is the angle, θ in degrees, between one of the chains and the vertical where it contacts the chandelier? Write an expression for FT,y, the magnitude of the y-component of the tension in one chain, in terms of the given information and variables available in the palette. FT,y = Using your previous results, find the tension, FT in Newtons, in one chain. FT =
- The Drag Force on a race car travelling with a velocity of vis given by, FD = 1/2 CD APV ² Where: V = VELOCITY A = Frontal area of CAR IN M² = 1.289 m² P = density of air = 1.2754 kg/m³ Co = Coefficient drag = 0.9 The race car varies in speed from 18M/S to 55 m/s during a race T a using these speed and the Cp Valve allocated derive an arithmetic progression for the Dray force across the Velocity range Do Fur & Terms a+ (^-1)dA high-performance dragster with the mass of 1390 kg can accelerate at a rate of a=22 m/s^2. randomized Variables M=1390 kg A= 22m/s^2 (A) write an expression for the magnitude of the net force, f net,  that propels the dragster forward in terms of the variables provided. (B) if the track is L=400m long, what is the numerical value of the dragsters final speed, vf in m/s?Use the following constants if necessary. Coulomb constant, k = 8.987 × 10º N · m² /C². Vacuum permitivity, €o = 8.854 × 10-12 F/m. Magnitude of the charge of the electron, e = -1.60217662 × 10–19 C. Mass of the electron, me = 9.10938356 x 10–31 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, µC means micro coulomb . +Y (8, –7), q2 = -48 µC at p2 = (-8, 11) and q3 = 21 µC at Coordinates of three charges in a 2D plane is given as follows: q1 = 39 µC at p1 P3 = (-14,9). These coordinates are given in centimeters.
- From Fig. P-014, P is directed at an angle a from x-axis and the 200 N force is acting at a slope of 5 vertical to 12 horizontal. a. Find P and a if the resultant is 500 N to the right along the x-axis. b. Find P and a if the resultant is 500 N upward to the right with a slope of 3 horizontal to 4 vertical. c. Find P and a if the resultant is zero. 12 200 N Figure P-014Braces are used to apply forces to teeth to realign them. Shown in this figure are the tensions applied by the wire to the protruding tooth. Randomized Variables T = 27 N ▷ A What is the magnitude of the net force that is exerted on the tooth (in N) if the tension in the wire is 27 N? 15° F app 15°A particle of mass begins to move at t = 0) from point r(t = 0) = at velocity e(t = 0) = t. The particle moves along the axis in 1 dimensional motion. The only external force acting on the body during its motion is drag force due to air resistance which is quadratically proportional to the velocity of the particle: F₁ = -² where c is a known real and positive constant. a. Which function describes the velocity of the body as a function of time (A and a are real and positive constants)? Hint: write down the equation of motion in terms of the velocity and its derivatives, and check which of the following function is a solution to this equation. O a. O b. OC. Ae-at O d. Asin(at) Oe. at +A Of Ae b. Find the constants A and a. O a. A=t, a== O b. Acto, a = A of3 O d. Aa= A 1+1 Oc. A t,a== C m Of A-cre, a= O a. O b. Oe. At, a=-= O f c. Find the acceleration of the body as a function of its position coordinater. O C. C₂ 171 m O a zo to Ob O d. (x Oc =e 171 m 778 Oe. cro _ ಆಫ್ ಟೆ + m m C-(-3)…