An object A moves along the x-axis according to the equation: x(t) = 3.5t2+1.7t+14.0 where x is in meters while t is in seconds, the other object B moves along the x-axis with constant speed 10.0 m/s. At what time the object A has the same instantaneous velocity as the object B? State your answer in seconds to the nearest 0.01s.

An object A moves along the x-axis according to the equation: x(t) = 3.5t2+1.7t+14.0 where x is in meters while t is in seconds, the other object B moves along the x-axis with constant speed 10.0 m/s. At what time the object A has the same instantaneous velocity as the object B? State your answer in seconds to the nearest 0.01s.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 11P: A particle moves along the x axis according to the equation x = 2.00 + 3.00t 1.00t2, where x is in...

See similar textbooks

Similar questions

The position of a particle moving along the x axis varies in time according to the expression x = 3t2, where x is in meters and t is in seconds. Evaluate its position (a) at t = 3.00 s and (b) at 3.00 s + t. (c) Evaluate the limit of x/t as t approaches zero to find the velocity at t = 3.00 s.
The velocity of a particle is given by v = 23t2 - 110t + 52, where v is in meters per second and t is in seconds. Plot the velocity v and acceleration a versus time for the first 6.4 seconds of motion and evaluate the velocity when a is zero. Make the plots and then answer the questions. Questions: When t = 0.8 s, V = i m/s, a = i m/s2 When t = 3.7 s, V = i m/s, a = i m/s? When t = 4.7 s, V = i m/s, a = i m/s? When a = 0, V = m/s
We are standing on the top of a 1040 feet tall building and launch a small object upward. The object's height, measured in feet, after t seconds is h(t) = 16t? + 128t + 1040. A) What is the object initial velocity? ft/second B) What is the highest point that the object reaches? feet
An antelope moving with constant acceleration covers the distance 65.0 mm between two points in time 7.00 ss. Its speed as it passes the second point is 16.0 m/sm/s. What is its speed at the first point? Express your answer with the appropriate units. v = What is the acceleration? Express your answer with the appropriate units. a=
At time t = 0, a particle has a velocity of m v = 4.00. The following graph shows the particles a(t) S acceleration vs. time. a. What was the particle's velocity at t = 3.00s ? 2 4 t b. What was the particle's instantaneous acceleration time(s) at t = 3.00s ? С. What was the average acceleration between t = 1.00s and t = 3.00s ? 4- 2. acceleration(m/s)
An object has an acceleration defined by the equation a=5t+4 (m/s^2) where "t" is in seconds. The initial velocity of the object is -10 m/s and started at a position s = 40m. 1. What is the initial magnitude of the acceleration of the object? Express your answer in unit of m/s^2 2. What is the velocity of the object after 4s? Express your answer in unit of m/s. 3. What is the position of the object after 4s? Express your answer in unit of m.
The vertical displacement (in m) of a plane is 1.5 t2 up; t is the time (in s) after takeoff. The plane releases a package 2.0 s after takeoff. What is the magnitude of the velocity (in m/s) when the packaged is released? Report your answer in the appropriate number of significant digits. Answer value
An object moves in one dimensional motion with constant acceleration a = 4.5 m/s². At time t = 0 s, the object is at xo = 2.9 m and has an initial velocity of vo = 4 m/s. How far will the object move before it achieves a velocity of v = 7 m/s? Your answer should be accurate to the nearest 0.1 m.
A ball is thrown straight down with an initial speed of 2.0 m/s from a height of 15 m. What is the position of the ball after 3.0 s, in meters? Use g = 9.8 m/s2. Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement
The displacement of a particle is given by s = 4t³ - 60t² + 100t -58 where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 13 seconds of motion. After you have made the plots, answer the questions. Questions: At t = 1.8 S= i fty = i ft/seca = i ft/ser sec, At t = 6.6 i S= fty = i ft/seca = i ft/se sec, Att = 9.8 sec, i fty = ft/seca = S = i ft/ser The velocity is zero when t = i sec and when t = sec
A sports car driver turned his car 15.0 km [E 30.0° N], and then turned again 30.0 km [W 45.0° N] to get back on track. If the diversion lasted a total of 2.00 minutes, what was the average velocity of the car, in m/s? Include diagrams to help you solve the question.
A miniature quadcopter is located at xi= 2.00 m and yi = 4.50 m at t = 0 and moves with an average velocity having components vave, x = 1.50 m/s and vave, y = -1.00 m/s. What are the x-coordinate at time t = 2.00 s? _ m y-coordinate at time t = 2.00 s?_ m