An insulated heated rod with spatially heat source can be modeled with the Poisson equation. of T = -f(x) dx² Given: A heat source f(x) = 0.12x3-2.4x² + 12x and the boundary conditions 7(x = 0) = 40°C and 7(x= 10) = 200 °C Solve the ODE using the shooting method. (Round the final answer to four decimal places.) Use 4th order Runge Kutta. The temperature distribution at x = 4 is K.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.7: More On Inequalities
Problem 44E
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An insulated heated rod with spatially heat source can be modeled with the Poisson equation.
T
d1 = -f(x)
Given: A heat source f(x) = 0.12x³ - 2.4x² + 12x and the boundary conditions 7(x = 0) = 40°C and 7(x= 10) = 200 °C
Solve the ODE using the shooting method. (Round the final answer to four decimal places.) Use 4th order Runge Kutta.
The temperature distribution at x = 4 is
K.
Transcribed Image Text:Required information An insulated heated rod with spatially heat source can be modeled with the Poisson equation. T d1 = -f(x) Given: A heat source f(x) = 0.12x³ - 2.4x² + 12x and the boundary conditions 7(x = 0) = 40°C and 7(x= 10) = 200 °C Solve the ODE using the shooting method. (Round the final answer to four decimal places.) Use 4th order Runge Kutta. The temperature distribution at x = 4 is K.
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