An electron is projected at an angle of 28.8° above the horizontal at a speed of 8.08x105 m/s in a region where the electric field is E = 393 j N/C. Neglecting the effects of gravity, calculate the time it takes the electron to return to its initial height. 1.42E-8 s Submit Answer Incorrect. Tries 1/6 Previous Tries Calculate the maximum height it reaches. Submit Answer Tries 0/6 Calculate its horizontal displacement when it reaches its maximum height. Submit Answer Tries 0/6

College Physics
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ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter18: Electric Charge And Electric Field
Section: Chapter Questions
Problem 46PE: (a) Using the symmetry of the arrangement, determine the direction of the electric field at the...
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An electron is projected at an angle of 28.8° above the horizontal at a speed of 8.08×105 m/s in a region where the electric field is E = 393 j N/C. Neglecting the effects of gravity, calculate the time it takes the electron to return to its initial height.
1.42E-8 s
Submit Answer Incorrect. Tries 1/6 Previous Tries
Calculate the maximum height it reaches.
Submit Answer Tries 0/6
Calculate its horizontal displacement when it reaches its maximum height.
Submit Answer Tries 0/6
Transcribed Image Text:An electron is projected at an angle of 28.8° above the horizontal at a speed of 8.08×105 m/s in a region where the electric field is E = 393 j N/C. Neglecting the effects of gravity, calculate the time it takes the electron to return to its initial height. 1.42E-8 s Submit Answer Incorrect. Tries 1/6 Previous Tries Calculate the maximum height it reaches. Submit Answer Tries 0/6 Calculate its horizontal displacement when it reaches its maximum height. Submit Answer Tries 0/6
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