An electron is circularly orbiting a proton. The magnitude of acceleration of the electron is 1.44×10–8 m/s2 . What is the electron’s orbital radius?
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An electron is circularly orbiting a proton. The magnitude of acceleration of the electron is 1.44×10–8 m/s2 . What is the electron’s orbital radius?
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- In Bohr’s model of the H atom, an electron orbits a proton in a circle of radius 5.28 x 10-11 m with a speed of 2.18 x 106 m/s. What is the acceleration of the electron in this model?A vector field is defined by: F (x,y,z) = -xi - yj + zk Select the option that gives F expressed in cylindrical coordinates. A. F (r,ø,z) = -reø + zezB. F (r,ø,z) = (-x cos ø - y sin ø) er + (x sin ø - y cos ø) eø + zez C. F (r,ø,z) = - rer + zez D. F (r,ø,z) = reø + zez E. F (r,ø,z) = (x sin ø - y cos ø) er + (-x cos ø - y sin ø) eø + zezIf [x, p]=in and π = _—_p²+ -—-k x², , evaluate the commutator [.]. 2m 00 O O P m iħ 2m -P ħ iħ ħ m 2m iħ m 2m -P -P -P iħ m
- A charged particle is on an x-y plane. The particle starts from the origin, and begins by moving 14.0 centimeters, at an angle of 21.1o below the positive x-axis. The particle then changes direction and travels 11.1 cm at an angle of 38.8o above the positive x-axis. What is the particle’s displacement vector after these two motions? 17.7 cm, 6.71o above the positive x-axis 21.8 cm, 5.03o below the positive x-axis 21.8 cm, 5.03o above the positive x-axis 17.7 cm, 6.71o below the positive x-axisTwo blocks, M=B.00 kg and m=2.00 kg are being pulled across a rough floor(u k=0.14) by a force of FO= 68N directed 52 degrees above the horizontal, as shown. The top block m cannot slide on the bottom block so the system can be treated as a single 10.0 kg block which we will call MT Fo, M-2.0 ks 520 M-8.0kgQuestion: The polar coordinates of a point are 50m and . Then, what are its Cartesian coordinates? A. 2.75i+ 4.763j m, B. -2.75i- 4.763j m, C. 2.75i - 4.763j m, D. 4.763j m, E. -2.75i + 4.763j m,
- Find v and a if z = cos 2t + i sin 2t. Can you describe the motion?Given p with magnitude of 40 and a direction of 25°, q with magnitude of 75 and a direction of 270°, and r with magnitude of 30 and a direction of 220°, what is the magnitude of p + q + r? Round to the thousandths place. a 42.379 b 68.926 c 76.232 d 78.509The figure shows four vectors A, B, C and D having magnitudes 12.0 m, 10.0 m, 8.0 m, and 4.0 m, respectively. The sum of these four vectors is y B 30° + 30° X D 1076 2 48432 W S mand X M O a. 16.4 m at an angle 77.8° with respect to +X-axis. Ob. 16.4 m at an angle 12.3° with respect to +X-axis. c. 19.5 m at an angle 77.8° with respect to +X-axis O d. 19.5 m at an angle 12.30 with respect to +X-axis. O e. 8.20 m at an angle 77.8° with respect to +x-axis. F2 s # 3 E D 31, C M 80 $ 4 R F a FA % 5 V #tv ♫ T o FS G 6 B c Fo Y H & 7 N F7 p U 8 J DII FB 1 M ( 9 K F9 O A ) O 4 F10 L e e P il V F11 { 11 + [ C F12 command option O
- A charged particle is on an x-y plane. The particle starts from the origin, and begins by moving 14.0 centimeters, at an angle of 21.1degrees below the positive x-axis. The particle then changes direction and travels 11.1 cm at an angle of 38.8 degrees above the positive x-axis. What is the particle’s displacement vector after these two motions?The coordinate of point charge q1=15μC is P1 (15,3) , the coordinate of charge q2=22μC is P2 (10,6) and the coordinate of charge q3=3μC is P3 (7,6). The coordinates have centimeters as unit. The electric force on q2 due to q1 is denoted by vector F. a)Find x and y component of F. The electric force on q1 due to q2 is denoted by vector f. b) Find x and y component of f.An electron moving along X- axis has opposition given by x= 16t.et m. How far the electron is away from origin and when it momentarily stops?