An aluminum coffee mug has in inner diameter of 2.50 cm at room temperature (20.0° C). If someone accidentally leaves the cup on the stove burner its temperature could rise to 300° C. What would be the inner diameter then? (keep 4 significant figures in your answer) Linear coefficient of expansion for copper, Caluminum = 24 X 10-/C° Area coefficient of expansion for copper, Yaluminum = 48 X 10-6/C° Volume coefficient of expansion for copper, Baluminum = 72 X 10-6/C°

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Chapter1: Temperature And Heat
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An aluminum coffee mug has in inner diameter of 2.50 cm at room temperature (20.0°
C). If someone accidentally leaves the cup on the stove burner its temperature could
rise to 300° C. What would be the inner diameter then? (keep 4 significant figures in
your answer)
Linear coefficient of expansion for copper, Caluminum = 24 X 10-6/C°
Area coefficient of expansion for copper, Yaluminum = 48 X 10-/C°
Volume coefficient of expansion for copper, Baluminum = 72 X 106/C°
Transcribed Image Text:An aluminum coffee mug has in inner diameter of 2.50 cm at room temperature (20.0° C). If someone accidentally leaves the cup on the stove burner its temperature could rise to 300° C. What would be the inner diameter then? (keep 4 significant figures in your answer) Linear coefficient of expansion for copper, Caluminum = 24 X 10-6/C° Area coefficient of expansion for copper, Yaluminum = 48 X 10-/C° Volume coefficient of expansion for copper, Baluminum = 72 X 106/C°
Tc = TK - 273 ° C
T. +32
5
%3D
AL = a L,AT
AA = y A,AT y= 2a
AV = BV,AT B = 3a
Thermal Expansion
aL,AT
P1V1 = P2V2
Ti
AL =
T2
AA =y A,AT y = 2a
1/2 mv2 = 3/2kBT
AV = BV,AT ß = 3a
where kB is Boltzmann’s constant,
PV =
„RT
KB = 1.38 x 10-23 J/k
number of moles, n =
mass (grams)
molecular weight
Avogadro's number, NA = 6.02 x 1023
R = 8.31 J/mole-K
Transcribed Image Text:Tc = TK - 273 ° C T. +32 5 %3D AL = a L,AT AA = y A,AT y= 2a AV = BV,AT B = 3a Thermal Expansion aL,AT P1V1 = P2V2 Ti AL = T2 AA =y A,AT y = 2a 1/2 mv2 = 3/2kBT AV = BV,AT ß = 3a where kB is Boltzmann’s constant, PV = „RT KB = 1.38 x 10-23 J/k number of moles, n = mass (grams) molecular weight Avogadro's number, NA = 6.02 x 1023 R = 8.31 J/mole-K
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