Aluminum metal reacts with bromine according to the following unbalanced equation: Al (s) + Br₂ (1)→ AlBr3 (s) Suppose you want to make 8.90 g of aluminum bromide. (a) What mass of aluminum metal is needed? 4. (b) What mass of bromine is needed? (c) If only 8.84 g of aluminum bromide is obtained, what is the percent yield of AlBrz? Formula weights (g/mol): Al 26.9815 Br₂ 159.808 AlBr3 266.69

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter3: Equation, The Mole, And Chemical Formulas
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Aluminum metal reacts with bromine according to the following unbalanced equation:
Al (s) + Br₂ (1)→→ AlBr3 (s)
Suppose you want to make 8.90 g of aluminum bromide.
(a) What mass of aluminum metal is needed?
4.
(b) What mass of bromine is needed?
(c) If only 8.84 g of aluminum bromide is obtained, what is the percent yield of AlBr3?
Formula weights (g/mol): Al 26.9815 Br2 159.808 AlBr3 266.69
Transcribed Image Text:Aluminum metal reacts with bromine according to the following unbalanced equation: Al (s) + Br₂ (1)→→ AlBr3 (s) Suppose you want to make 8.90 g of aluminum bromide. (a) What mass of aluminum metal is needed? 4. (b) What mass of bromine is needed? (c) If only 8.84 g of aluminum bromide is obtained, what is the percent yield of AlBr3? Formula weights (g/mol): Al 26.9815 Br2 159.808 AlBr3 266.69
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