Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. CH3 + excess CH₂CH₂OH • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. Do not include counter-ions, e.g., Na", I", in your answer. • In cases where there is more than one answer, just draw one. NaOCH₂CH3
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- Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. CH3OH H3C CI • • • • You do not have to consider stereochemistry. Include all valence lone pairs in your answer. Do not include counter-ions, e.g., Na+, I", in your answer. In cases where there is more than one answer, just draw one.Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. CI + H₂N • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. OH • Do not include counter-ions, e.g., Na+, I¯, in your answer. • In cases where there is more than one answer, just draw one.Step 4a: Classify step. The target product is present, but the reaction is not over. The ethoxide ion has been regenerated. :0: :0: What is the key process in the next step of the mechanism? proton transfer formation of a o bond between nucleophile and electrophile loss of a leaving group carbocation rearrangement (e.g., methyl or hydride shift)
- Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. H3C HCI / H2O `NH2 reflux • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na", I, in your answer. • In cases where there is more than one answer, just draw one. opy aste Previous NextUse the dropdown menu to indicate whether the rate of the reaction shown below will increase, decrease, or remain the same when the reaction conditions are changed to X or to Y or to Z (see below). NaN3 'N3 Br CH3CN X: Change the leaving group from Br to CI Y: Increase the concentration of haloalkane Z: Increase the concentration of NaN3 X: choose your answer.. ^ Y: choose your answer... V Z: choose your answer... choose your answer... Remain the same Nex Decrease IncreaseAcyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. H3C. ... NH2 HCI/H₂O reflux • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na+, I, in your answer. • In cases where there is more than one answer, just draw one. + 4 n [ ?
- CH3 || CH3 H₂O H2SO4 CH3CHCH2CH2C—ОCH₂CH₂CHCH3 a. Draw the structure of the tetrahedral intermediate INITIALLY-FORMED in the reaction shown. • • • You do not have to consider stereochemistry. Do not include counter-ions, e.g., Na+, I, in your answer. In cases where there is more than one answer, just draw one. √n [ ChemDoodle Ⓡ b. Draw the structures of the organic products of the acyl transfer reaction. • You do not have to consider stereochemistry. Draw the neutral form of the products; no charges. Draw one structure per sketcher. Add additionalAlcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…Predict the products of this organic reaction: CH3 CH₂ || No reaction CH3 -CH-CH₂-CH3 + NaOH A Specifically, in the drawing area below draw the structure of the product, or products, of this reaction. (If there's more than one product, draw them in any arrangement you like, so long as they aren't touching.) If there aren't any products because this reaction won't happen, check the No reaction box under the drawing area. ? Click anywhere to draw the first atom of your structure. X Ś
- Draw the structure of the alkyl bromide and the nucleophile that will react in an Sy2 reaction to give the product shown. CN Alkyl bromide + Nucleophile H3C • You do not have to consider stereochemistry. Separate multiple reactants using the + sign from the drop-down menu.Answer the question below the reaction. O4S H3C H3C H3C OH In the first step of the reaction mechanism, which of the following is formed? CH3 H3C CH3 CH3 + Excess NH4Cl OH CH3 (+) -OH2 CH 3 CH3 OH CH3 H₂SO₁ CH3 CI ха +H2OFor the following reactions, determine which mechanism they will follow, explain why the substitution of the alkyl halide doesn't affect the mechanism in an elimination reaction a. draw the mechanism showing regiochemistry of both possible products b. determine which product would be the most stable and therefore the major product c. Draw reaction coordinate diagrams and write rate laws for each reaction mechanism you Br yo you HO