Absorption of Drugs The concentration of a drug in an organ at any time t (in seconds) is given by x(t) = 0.09 + 0.18(1 - -0.0291) where x(t) is measured in milligrams per cubic centimeter (mg/cm³). (a) What is the initial concentration of the drug in the organ? (Round your answer to two decimal places.) x(t) = 0.06 x mg/cm³ (b) What is the concentration of the drug in the organ after 15 sec? (Round your answer to four decimal places.) x(t) -0.1975 mg/cm³ x

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
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Absorption of Drugs The concentration of a drug in an organ at any time t (in seconds) is given by
x(t) = 0.09 + 0.18(1 - -0.029)
where x(t) is measured in milligrams per cubic centimeter (mg/cm³).
(a) What is the initial concentration of the drug in the organ? (Round your answer to two decimal places.)
x(t) = 0.06
x mg/cm³
(b) What is the concentration of the drug in the organ after 15 sec? (Round your answer to four decimal places.)
x(t) = 0.1975
mg/cm³
x
Transcribed Image Text:Absorption of Drugs The concentration of a drug in an organ at any time t (in seconds) is given by x(t) = 0.09 + 0.18(1 - -0.029) where x(t) is measured in milligrams per cubic centimeter (mg/cm³). (a) What is the initial concentration of the drug in the organ? (Round your answer to two decimal places.) x(t) = 0.06 x mg/cm³ (b) What is the concentration of the drug in the organ after 15 sec? (Round your answer to four decimal places.) x(t) = 0.1975 mg/cm³ x
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