"abcdefgh".subString(1, 3) returns O abc O bc O bcd O cde
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A: The above question is solved in step 2 :-
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A: Given: We have to discuss what is output of the following c++ Codes.
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- TRUE FALSE & is used to pass a parameter by value * is used as a reference operator * is called the dereference operatordef winning_card(cards, trump=None): Playing cards are again represented as tuples of (rank,suit) as in the cardproblems.pylecture example program. In trick taking games such as whist or bridge, four players each play one card from their hand to the trick, committing to their play in clockwise order starting from the player who plays first into the trick. The winner of the trick is determined by the following rules:1. If one or more cards of the trump suit have been played to the trick, the trick is won by the highest ranking trump card, regardless of the other cards played.2. If no trump cards have been played to the trick, the trick is won by the highest card of the suit of the first card played to the trick. Cards of any other suits, regardless of their rank, are powerless to win that trick.3. Ace is the highest card in each suit.Note that the order in which the cards are played to the trick greatly affects the outcome of that trick, since the first card played in the trick…Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eax
- int isbivisibley6(int num) (mu ) reture isDivisibleBy6( ); (num return 13 ( 1mum ) nUR num 10 ) return reture isDivisibleBy6( num/ 10 2 ( num num/10 sol) ); 12 ) 13 int main(O 14 ( int num 6003; (isDivisibleBy6( )) print ("Divisible" ); else print ("Not Divisible" ); return 0; 16 17 18 19 20 input Compilation taled due to foowing main.cif:10: error: too few arguments to function 'isDivisibleBy6' 6 return isDivisibleby6( ); main.cl: note: declared here 3| int isDivisibleBy6(int num) main.c: In function 'main': main.c:16:6: error: too few arguments to function 'isDivisibleBy6 16 | if( isDivisibleBy6( )) Apunun main.c3:5: note: declared here 3 int isDivisibleBy6(int numYou can dereference a smart pointer with the * operator. True FalseComplete the function ConvertToDecadesAnd Years to convert totalYears to decades and years. Return decades and years using the ElapsedDecades Years struct. Ex: 26 years is 2 decades and 6 years. 1 #include 2 3 typedef struct ElapsedDecadesYears_struct { int decadesVal;` 5 int yearsVal; 6) ElapsedDecadesYears; 7 8 Elapsed Decades Years ConvertToDecadesAndYears(int totalYears) { ElapsedDecades Years tempVal; /* Your code goes here */ 15 int main(void) { 8722878 25 26 } ElapsedDecadesYears elapsedYears; int totalYears; scanf("%d", &totalYears); elapsedYears = ConvertToDecadesAndYears (totalYears); printf("%d decades and %d years\n", elapsedYears.decadesVal, elapsedYears.yearsVal); return 0;
- Statement-.In the expression 48:(14*3), are the brackets necessary? What happens when you type 48:14*3?Code uses C++ language If the user chooses to generate a Pentagono This is a combination of a triangular shape and a square shape -- a symmetrictriangle sits on top of a rectangle.o The triangular shape must be symmetric about the vertical axis. There must beexactly one character in the first line, and the number of characters increases by2 in every successive lineo The rectangle shape must have LENGTH lines of height and all lines are 13characters wide.o Make sure to add delay to view a progressively growing pentagon, otherwise youwill just see the final shape. Code for triangle: for (int i = 1; i <= length; i++) { sleep (1); for (int j = length - i; j > 0; j--) cout << " "; for (int b = 1; b <= i; b++) cout << char(rdm) << " "; cout << endl; } Code for square: for (int row = 1; row <=…