TS 3Practice Problema. Wrice the nodal equations for the circuitshown; and solue for the nodal voltages.b. Determine rhe magnitude a nd polarity of thevo itage across each esistor.R4R3R5.R,6AR2.7AエAnswerV, = - 2.556 VV2 = 4.03 VR, = V, = - 2.556 V%3D%3DVR,= R = V, = 4.03 V%3DVR, = V2- V, = 6.586 VVRu%3Dんもト

In nodal analysis we apply KCL and ohms law to find node voltages Voltage across parallel element…

a. Write the nodal equations for the cireuit shown; and solue for the nodal voltages. b. Determine the magnitude and polarity of the vo itage across each resistor. R4 Practice Problem R3 Rs Ri エ 6A 7A Answer V2 = 4.03 V V,= - 2.556 V = - 2.556V %3D VR= R = V = 4.03 V VRu = V2- V, = 6.586 V

a. Write the nodal equations for the cireuit shown; and solue for the nodal voltages. b. Determine the magnitude and polarity of the vo itage across each resistor. R4 Practice Problem R3 Rs Ri エ 6A 7A Answer V2 = 4.03 V V,= - 2.556 V = - 2.556V %3D VR= R = V = 4.03 V VRu = V2- V, = 6.586 V

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

KVL and KCL

KVL stands for Kirchhoff voltage law. KVL states that the total voltage drops around the loop in any closed electric circuit is equal to the sum of total voltage drop in the same closed loop.

Sign Convention

Science and technology incorporate some ideas and techniques of their own to understand a system skilfully and easily. These techniques are called conventions. For example: Sign conventions of mirrors are used to understand the phenomenon of reflection and refraction in an easier way.

Question

TS 3
Practice Problem
a. Wrice the nodal equations for the circuit
shown; and solue for the nodal voltages.
b. Determine rhe magnitude a nd polarity of the
vo itage across each esistor.
R4
R3
R5.
R,
6A
R2.
7A
エ
Answer
V, = - 2.556 V
V2 = 4.03 V
R, = V, = - 2.556 V
%3D
%3D
VR,= R = V, = 4.03 V
%3D
VR, = V2- V, = 6.586 V
VRu
%3D
んもト

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