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- 1.) Propose the biosynthesis of 5-methylorsellinic acid: CH3 НО. CH3 `CO,H OHWhich of the structures below is that of О-а-D-glucopyranosy-(1->1)- а-D-glucoругanoside CH2OH CH2OH O. H H. он H. он H OH ÓH CH2OH HOH2 H. CH2OH CH2OH O. H H. он он H OH он CH2OH H. о, он он H он онL-Ala -NAM-NAG-NAM-NAG L-Ala D-Glu D-Ala DA Transpeptidase D-Ala DAP I D-Ala D-Glu I L-Ala NAG-NAM-NAG-NAM 21. Modification of the enzyme pictured (above) might result in resistance to A. quinolone B. streptomycin C. chloramphenicol D. penicillin E. trimethoprim
- Draw the products formed when -D-idose is treated with C6H5NHNH2 (excess), H+NAZO NHZ Ala-Cys-Glu -Tyr - Trp - Lys - Arg - His -Pro-G ly Glu pka 4.15 SH Tyr 10.10 Draw Charges Lys 10.67 Olt A3 12.10 +NH₂ Ntrm 2) Calculate net charge 3) write out I letter code 300 Ctim 3 juli of peptich (above) Ⓒ pH; 1,7,12The enzyme cytidine deaminase catalyzes the conversion of cytidine to uridine. Cytidine deaminase catalyzes the reaction through an addition of water across the cytidine 3,4-bond, forming a tetrahedral intermediate followed by the elimination of NH3 to form the product uridine. This is like the addition-elimination mechanism that we studied for adenosine deaminase. Cytidine deaminase НО. NH₂ N пOH OH cytosine R + H₂O cytidine The Km value for the substrate cytidine is 2.5 × 10-4 M, and the K; for competitive inhibition by the product uridine is 2.5 × 10-³ M. N R A reduced derivative of the product, 3,4,5,6-tetrahydrouridine was shown to be a fully reversible competitive inhibitor with a Ki of 2.4 x 10-7 M, a value approximately 10,000 times lower than that of the product uridine. NH₂ NH uridine HO. N R R = D-ribose HOH OH uridine 3NH uracil ring numbering H NH H H + NH3 H OH H 3,4,5,6-tetra- hydrouridine a.) Draw a structure of the intermediate that we predict to form during the…
- Modify methionine to show its zwitterion form. Select Draw с N 0 Templates S H More 1C || H0 C 1 с | CH₂ | CH₂ | S 1 CH3 HIN I N-H Erase Q 2 QSecond letter A UUU UCU) UC UCA UCG UAU UUC Phe UUA Tyr UGU UGCJ Ser UAA Stop UGA Stop A UAG Stop UGG Trp UUG Leu CAUHIS CUU CUC CUA CUG CCU* C ССА CCG CGU His САС Leu CGC Arg CGA Pro CAA Gin CGGJ Gln Which amino acid is carried by the TRNA with the anticodon 5'-UCA-3? ACU ACC ACA AAU AAC. AGU AGC AGA AUU Ser Asn AUC Ile A AUA Thr AAA Lys AAG Lys AGG Arg AUG Met ACG GAU GGU] GUU GUC GUA GUGJ GCU GCC GCA GCG GAC Asp Ala GAA GGC Gly GGA Val GAG Glu GGGJ Isoleucine. None-this is a stop codon. Aspartic acid. Histidine. IV. Leucine O V. Third letter UCAG UCAG UCAG First letterIn serine protease catalytic triad mechanism, the first and second products that leaves the active site are Carboxylic acid and amide respectively Amide and carboxylic acid respectively Ester and amide respectively Carboxylic acid and ester respectively
- Stapphylococcus aureus V8 protease cleaves at the C-termini of Asp and Glu. How many fragments do you expect to see if the polypeptide AWTYDLKCVINRMRASTFEYY is subjected to complete digestion by the V8 protease? 1 2 3 4I. A protein, X, was Isolated from a pathogenlc mlcroorganism. The proteln Is a vlrulence factor whose path0genlclty lies In a heptapeptide of unknown sequence. After trypsin cleavage of the heptapeptide from protein X, the peptlde's compOsition and sequence was determined. The fOllowing were the results of the sequenclng process: 1. When the peptide was treated with dinitrofluorobenzene (DNFB), DNP-asp and a mixture of amino acids were produced. 2. When the same Intact peptide was treated with streptococcal protease, a pentapeptide of composition asp, asN, cys, gly and ser and 2 amlno acids were released. 3. When the heptapeptlde was also treated with hydrOxylamine HCI, a tripeptide and a tetrapeptide were obtained. The C-terminal amino acid of the tripeptide was asN. 1) What is the sequence of the heptapeptide if it is composed of cys, asp, lys, asN, gly and ser only? 2) What is the pl of the heptapeptide?The macrolide below is a bacteria produced toxin. The primer was acetyl-Co-A. Three possible extenders are also shown A) malonate-Co-A B) methylmalonate-Co-A and C) ethylmalonate- Со-А. Indicate which extenders were used using this format: XA yB zC Meaning x molecules of A, y molecules of B and z molecules of C он COA CH3 А А но CH3 CoA В но ČH3 H3C C C HO но COA CH3 Enter Your Answer: