a) What is the book value of the system at the end of year three if Straight line method is used? b) Suppose that after depreciation of the system for two years with straight line, the company decides to switch to the decline method for the reminder of the system life (depreciation rate 30 %). What is the system Book Value at the end of four years?
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- I need the solution in handwriting The following are the cost of a system and the useful life is five years. The salvage value for depreciation purpose is equal to 25% of the hardware cost Item Cost Hardware $170,000 Training Installation $18,000 $18,000 a) What is the book value of the system at the end of year three if Straight line method is used? b) Suppose that after depreciation of the system for two years with straight line, the company decides to switch to the decline method for the reminder of the system life (depreciation rate 30%). What is the system Book Value at the end of four years? (The following table summarizes the financial data for a proposed new asset. The issue is how long the asset should be kept. Assume an interest rate of 12% and delermine the economic service life of the anset. End of YearN) Investment cost O&M Cost Salvage value $14,000 $3.400 $8.000 $4600 $6.000 $5.800 $4,000 01 year O2 years 3 years O Not enough informationA new robot has a first cost of $380,000, and an annual operating cost of $88,000 in years 1 and 2, increasing by $10000 per year thereafter. The salvage value of the system is $25,000 regardless of when the system is retired within its maximum useful life of 5 years. Using a MARR of 14% per year, determine the ESL and the respective AW value of the system ESL: a) 1 year b) 4 years c) 5 years d) 3 years AW value of system: a) $204,860 b) $336,284 c) $97,953 d) $496,200
- A certain power plant is considering two alternatives with regards to a hydraulic equipment which it needs. The following alternatives were considered. Equipment A Equipment B First Cost: P 120,000 P 136,000 Salvage Value: P 15,000 0 Life: 6 years 8 years Annual Maintenance: P 9,000 P 7,000 Compute the difference between the equivalent present worth of the two alternatives if interest rate is 7% compounded annually. Select one: a. P 26,410 b. P 30,108 c. P 28,312 d. P 24,895If B = $400,000, n = 6 years, and S is estimated at 15% of B for a new pavement recycling machine, use the SYD method to determine (a) the book value after 3 years, and (b) the rate of depreciation and the depreciation amount in year 4.From the given values below, which machine should be selected using (a) Present worth Method and (b) Future worth Method if interest rate is 10% per year? Machine A B Initial Cost (Php) Annual Operating Cost 146,000 15,000 80,000 10,000 3 220,000 10,000 75,000 25,000 Annual Revenue Salvage Value Useful Life (years) 6
- Answer the question. A challenger asset with a maximum useful life of 6 years has a first cost of $43,000 and an estimated annual operating cost of $6250. The market value is expected to decrease by $6450 each year for the next 6 years. If the MARR is 10% per year, fill in blanks below to correctly represent the equation for calculating the EUAC at the end of year 2. (HINT: skip $ and comma symbols) EUAC2 = 43,000 ( 10%, 2) + (43,000 - 6450*2) ( 10%,2)7) Consider the following information: Asset Cost $56,000Salvage value 1,000Life 10 yearsDepreciation method Straight Line a. What is the depreciation in year 3? b. What would the depreciation in year 4 be if at the beginning of the year we think that the total asset life will be only 8 years instead of 10 years?An engineer must choose between two technically equivalent alternatives, A and B. Based upon the data in the table below over the 12year analysis period and an interest rate of 9%, the PW of machine A is: A B First Cost $3,000 $6,000 Annual Maintenance $500 $300 End of Useful Life Salvage Value $700 $1,000 Useful Life 5 years |15 уears O PWA=-3000-3000(P/F,9%,5)-3000(P/F,9%,10)-500(P/A,9%,15)+700(P/F,9%,5)+700(P/F,9%,10)+700(P/F,9%,15) O PWA=-3000-3000(P/F,9%,10)-500(P/A,9%,15)+700(P/F,9%,5)+700(P/F,9%,10)+700(P/F,9%,15) O PWA=-3000-3000(P/F,9%,5)-3000(P/F,9%,10)-500(P/F,9%,15)+700(P/F,9%,5)+700(P/F,9%,10)+ 700(P/F,9%,15) O PWA=-3000-3000(P/F,9%,5)-3000(P/F,9%,10)-500(P/A,9%,10)+700(P/F,9%,5)+700(P/F,9%,10)+ 700(P/F,9%,15)
- The table given below lists the relevant cost items for a specific system purchase. The operating expenses for the new system are $10,000 per year, and the useful life of the system is expected to be five years. The salvage value for depreciation purposes is equal to 25% of the hardware cost. Cost Item Cost Hardware $160,000 Training $15,000 Installation $15,000 a) What is the Book Value (BV) of the device at the end of year three if the Straight Line (SL) depreciation method is used? b) Suppose that after depreciating the device for two years with the SL method, the firm decides to switch to the double declining balance depreciation method for the remainder of the device's life (the remaining three years). What is the device's BV at the end of four years?The AW values for retaining a presently owned machine for additional years are shown in the table. Note that the values represent the AW amount for each of the n years that the asset is kept, i.e., if it is kept 5 more years, the annual worth is $−95,000 for each of the 5 years. Assume that future costs remain as estimated for the replacement study and that used machines like the one presently owned will always be available. (a) What is the ESL and associated AW of the defender at a MARR of 12% per year? (b) A challenger with an ESL of 7 years and an AWC = $-88,000 per year has been identified. Which AW will be less for the respective ESL periods? Retention Period, Years AW Value, $ per Year 1 -87,000 2 -93,000 3 -85,000 4 -83,000 5 -95,000 a) The ESL of the defender is_____ year(s) with the lowest AW of $_________ . b) The______________ has the lower AW at _________$ for n equal to ______ .The AW values for retaining a presently owned machine for additional years are shown in the table. Note that the values represent the AW amount for each of the n years that the asset is kept, i.e., if it is kept 5 more years, the annual worth is $-95,000 for each of the 5 years. Assume that future costs remain as estimated for the replacement study and that used machines like the one presently owned will always be available. (a) What is the ESL and associated AW of the defender at a MARR of 12% per year? (b) A challenger with an ESL of 7 years and an AWC = $-82,000 per year has been identified. Which AW will be less for the respective ESL periods? AW Value, $ per Year -81,000 -94,000 -83,000 -93,000 -95,000 Retention Period, Years 1 2 3 4 a) The ESL of the defender is year(s) with the lowest AW of $ b) The |(Click to select) has the lower AW at $| for n equal to