A triangular number is a number that is the sum of the integers from 1 to some integer n. Thus 1 is a triangular number because it is the sum of the integers from 1 to 1; 6 is a triangular number because 1+2+3=6. Given the non-negative integers m and n (with m < n), create a list of the triangular numbers between (and including) m and n. Thus if m is 3 and n is 20, the list would be: [3, 6, 10, 15]. Assign the list to the variable triangulars.
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- CCC '13 J1 - Next in line Canadian Computing Competition: 2013 Stage 1, Junior #1 You know a family with three children. Their ages form an arithmetic sequence: the difference in ages between the middle child and youngest child is the same as the difference in ages between the oldest child and the middle child. For example, their ages could be 5, 10 and 15, since both adjacent pairs have a difference of 5 years. Given the ages of the youngest and middle children, what is the age of the oldest child? Input Specification The input consists of two integers, each on a separate line. The first line is the age Y of the youngest child (0A decreasing sequence of numbers is a sequence of integers where every integer in the sequence is smaller than all other previous integers in that sequence. For example, •35, 16, 7, 2, 0, -3, -9 is a decreasing sequence of numbers. 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B × ACreate a function that returns the nth catalan number. In combinatorial mathematics, the Catalan numbers form a sequence of natural numbers that occur in various counting problems, often involving recursively-defined objects. They are named after the Belgian mathematician Eugène Charles Catalan (1814-1894). For more info, check out the resource tab. Examples getCatalanNumber (0) → 1 getCatalanNumber (6) → 132 getCatalanNumber (8) 1430 Notes Inputs are zero and positive integers.Python Lab: Dr.D has invented yet another invention: the hateinator. He wants to test it on a group of N people (numbered 1 through N). The hateinator may be used any number of times; to use it once, Dr.D should divide these N people into two groups and press the fire button on the hateinator. We call each such grouping a Doofish set. Afterwards, there will be hatred between each two people who were in different groups. 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Two rectangles are said to overlap, if there is a common point in both of them. [If a rectangle is entirely contained in another, they are still said to “overlap”, even though their lines don’t cross.]def findOccurrences(s, ch): lst = [] for i in range(0, len(s)): if a==s[i]: lst.append(i) return lst Use the code above instead of enumerate in the code posted below. n=int(input("Number of rounds of Hangman to be played:")) for i in range(0,n): word = input("welcome!") guesses = '' turns = int(input("Enter the number of failed attempts allowed:")) def hangman(word): secrete_word = "-" * len(word) print(" the secrete word " + secrete_word) user_input = input("Guess a letter: ") if user_input in word: occurences = findOccurrences(word, user_input) for index in occurences: secrete_word = secrete_word[:index] + user_input + secrete_word[index + 1:] print(secrete_word) else: user_input = input("Sorry that letter was not found, please try again: ") def findOccurrences(s, ch): return [i for i, letter in enumerate(s) if letter == ch] *** enumerate not discussed in…def fun_a(cards): """ cards is a list of int numbers ranging between 0 to 12 inclusive. We use the number to represent the card's rank in a deck of card. 0 is '2', 1 is '3', ...,9 is 'J', 10 is 'Q', 11 is 'K' and 12 is 'A' This function is to check if there is four of a kind in the cards (4 cards of the same rank) and a fifth card as a kicker to form a four of a kind hands with 5 cards total. The 5 cards look like this: x x x x y (x might be the same as y). If there is more than one way to form such a hand with given cards, choose x that has the highest ranking (that has 4 cards of rank x), and choose y that has the highest ranking in the remaining cards after removing 4 x's. return (x, y) if such a hand exists. otherwise return None. """SEE MORE QUESTIONS