Answered: A three-phase 240-volt table saw…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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A three-phase 240-volt table saw requires 36 kW. Calculate the load current for the table saw. The current and the voltage are out of phase by an angle of 32 degrees.

Hint 1: 30kW here refers to working power, not apparent power.

Hint 2: The equation for working three-phase power is found in Eq. 12.21.

Hint 3: Refer to Figure 12.12 about calculating theta

The working power P, in watts (W), is the component of AC power that performs useful work. In practical applications, power P always refers to working power. For single-phase power,
(12.20)
For three-phase power,
(12.21)
PEx I x PF
= ExIx cos
P = 1.73 x E x I x PF
= 1.73 x Ex I x cos 0
= 1.73 x Pa x cos

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