a) The reaction of NO2 has been studied as a function of temperature. For the following decomposition reactions, the rate constant is 2.7 × 10-2M-1s-1 at 227 °C and 2.4 x 10-1M-1s-1 at 305 °C. 9. 2 NO2 → 2 NO + 02 Calculate the activation energy for this reaction. 9. b) Nitrogen oxide converts ozone into molecular oxygen as follows: 03 + NO → 02 + NO2 k[03][NO]. Show which of the following The experimental rate law is: Rate = mechanism/mechanisms are consistent with the experimental rate law. Mechanism 1: 03 + NO → 02 + NO3 (slow) 0 + 03 → 2 02 (fast) NO3 + NO → 2 NO2 (fast) Mechanism 2: 03 = 02 + 0 (fast) NO + 0 → N02 (slow) Mechanism 3: 03 + NO → 02 + NO2 (slow)

Chemistry for Engineering Students
4th Edition
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Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.35PAE: 11.35 For the reaction 2 NO(g) + 2 H?(g) — N,(g) + 2 H,O(g) at 1100°C, the following data have been...
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a) The reaction of NO2 has been studied as a function of temperature. For the following decomposition
reactions, the rate constant is 2.7 × 10-2M-'s-1 at 227 °C and 2.4 x 10-1M-1s-1 at 305 °C.
9.
2 NO2 → 2 N0 + 02
Calculate the activation energy for this reaction.
9.
b) Nitrogen oxide converts ozone into molecular oxygen as follows:
Оз + NO -> 02 + NO2
The experimental rate law is: Rate = k[03][NO]. Show which of the following
mechanism/mechanisms are consistent with the experimental rate law.
Mechanism 1:
03 + NO → 02 + NO3
(slow)
0 + 03 → 2 02
(fast)
NO3 + NO → 2 NO2
(fast)
Mechanism 2:
032 02 + 0
(fast)
NO +0 → N02
(slow)
Mechanism 3:
03 + NO → 02 + NO2
(slow)
Transcribed Image Text:a) The reaction of NO2 has been studied as a function of temperature. For the following decomposition reactions, the rate constant is 2.7 × 10-2M-'s-1 at 227 °C and 2.4 x 10-1M-1s-1 at 305 °C. 9. 2 NO2 → 2 N0 + 02 Calculate the activation energy for this reaction. 9. b) Nitrogen oxide converts ozone into molecular oxygen as follows: Оз + NO -> 02 + NO2 The experimental rate law is: Rate = k[03][NO]. Show which of the following mechanism/mechanisms are consistent with the experimental rate law. Mechanism 1: 03 + NO → 02 + NO3 (slow) 0 + 03 → 2 02 (fast) NO3 + NO → 2 NO2 (fast) Mechanism 2: 032 02 + 0 (fast) NO +0 → N02 (slow) Mechanism 3: 03 + NO → 02 + NO2 (slow)
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