A synchronous generator supplies rated power at 0.8 pf lagging.ra 0.015p. u., andxl = 1p.u. . Find out the possible terminal voltage. In case of the practical operation, which terminal voltage is more feasible? =
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- Does Clampor circuit change the peak-to-peak (i.e., rms value)? JustfyA 6 pole wave wound d.c. shunt generator has 500 conductors. A generator delivers 50 kW of power at 250 voltage at full load. The resistance of the field circuit is 125 2. Actual brush shift is 10°. Then find the demagnetizing and cross magnetizing ampere turns per pole and how many additional turns must be wound on each pole to eliminate the demagnetizing effect.The frequency of voltage generated in SG depends on: Select one:a. Number of polesb. number of poles and speed rotationc. Field currentd. Rotor speede.Number of poles, speed rotation and type of winding
- The O.C.C. data for separately-excited generator when run at 130 r.p.m. on open circuit is E.M.F. (V) : 12 44 73 98 113 122 127 Exciting current : 0 0.2 0.4 0.6 0.8 1.0 1.2 Deduce the curve of e.m.f. and excitation when the generator is running separately-excited at 1000 r.p.m.To what voltage will the generator build up on no-load when running at 1000 r.p.m.? To what voltage will thegenerator build up on no-load when running at 100 r.p.m. if the total field resistance is 100 Ω ?Two generators are supplying a load. Both the generators have a no-load frequency of61.5 Hz and the slope sp of 1 MW/HZ. If they are supplying a real load of 2.0 MW at 0.8 pflagging, what would be the system frequency and power sharing between two generators?What measures can be taken to make the frequency 60 HZ. If an additional 1.0 MW load isconnected to the existing one what would the system frequency be.Question: A 4 Pole DC Generator Is Wounded Lap. It Rotates At 500rpm To Be Able... A 4 pole DC generator is wounded lap. it rotates at 500rpm to be able to generate 150 V of open circuit voltage. What is the percentage decrease in the exixting flux per pole if a frequency of 10 rps can produce 120 V? %.
- Maz a) A sinewave is having a frequency of 50 Hz and instantaneous value of 250 Volts at 1.3 milli seconds. Find D The maximum value of sinusoidal voltage waveform and i) The value of voltage at 2.1 milli seconds. b) Determine the instantaneous equation for the voltage waveform shown in figure, if Vp=100 Volts, Time period is 10 milli seconds and 0 =40 degrees. on Vp Upload your Answers steps in the "Final Answer Submission" Link provided in the Moodle. a) (i) Maximnum value = a) (ii) Value of voltage at 2.1 ms = b) Angular frequency =• - 1800 pm In a two pole 3-p synchronous generator, the peak flux of rotor magnetic field is o5Tand the rotor rate of rotation is 1800 rpm. The stator windings have a surface area of 0.1 m? and there are 50 turns per Bmax : 0.5T, 0.5T coil. The machine is A-connected. A: 0-1 m? N: 50 a) What is the RMS phase and line voltage of the generator? b) Write the three stator phase voltages as functions of time.Comment briefly on the relationship between input and output power at varying excitation levels and on the relationship between excitation and power factor or reactive power, when the synchronous machine is connected to an infinite busbar
- The O.C.C. data for separately-excited generator when run at 130 r.p.m. on open circuit isE.M.F. (V) : 12 44 73 98 113 122 127Exciting current : 0 0.2 0.4 0.6 0.8 1.0 1.2Deduce the curve of e.m.f. and excitation when the generator is running separately-excited at 1000 r.p.m.To what voltage will the generator build up on no-load when running at 1000 r.p.m.? To what voltage will thegenerator build up on no-load when running at 100 r.p.m. if the total field resistance is 100 Ω ?Two identical 2,000 kW alternator operates in parallel. The governor of the first machine is such that the frequency drops uniformly from 50 Hz at no-load to 48 Hz at full-load. The corresponding uniform speed drop of the second machine is 50 Hz to 47.5 Hz. What is the maximum load that can be delivered without overloading either machine?9.09 The flux density distribution in the air-gap of a certain generator is such that it contains a fundamental, a third harmonic, and a fifth harmonic. The flux per pole due to the fundamental distribution is 9 x 10-3 weber, that due to the third harmonic distribution is 0.9 x 10-3 weber, that due to the fifth harmonic distribution is 0.4 x 103 weber. There are four armature slots per phase per pole, the connection are made for three-phase wye. and the coil pitch is 12/15. The frequency is 60 cycles and the generator has 4 poles. (a) Calculate the emf/turn. (b) If there are six turns/coil and two coil sides/slot, calculate the emf per phase. (c) Calculate the emf between line terminals. Ans. 2.32V; 212V; 364V